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yarga [219]
3 years ago
7

A catapult with a just-ejected ball flying through the air. A catapult's lever holds a cannonball. The lever is attached to a ti

ghtly held rope. When the rope is released, the lever springs forward and launches the cannonball. When the rope is held tightly, which form of energy does it possess? thermal nuclear gravitational elastic
Physics
2 answers:
VladimirAG [237]3 years ago
5 0

Answer:

he string has POTENTIAL ELASTIC energy

Explanation:

he catapult is a very good example of energy transformations.

Initially when the string is taut it has an elastic potential energy, when releasing the lever it is transformed into cinetic energy in the ball until it shoots out.

Consequently the string has POTENTIAL ELASTIC energy

victus00 [196]3 years ago
4 0

Answer:

The answer is elastic

TRUST ME

Explanation:

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Problem 9: Suppose you wanted to charge an initially uncharged 85 pF capacitor through a 75 MΩ resistor to 90.0% of its final vo
Bingel [31]

Answer:

t=14.678\times 10^{-3}s

Explanation:

Given:

Capacitance, C = 85 pF = 85 × 10⁻¹² F

Resistance, R = 75 MΩ = 75×10⁶Ω

Charge in capacitor at any time 't' is given as:

Q=Q_o(1-e^{-\frac{t}{RC}})

where,

Q₀ = Maximum charge = CE

E = Initial voltage

t = time

also, Q = CV

V= Final voltage = 90% of E = 0.9E

thus, we have

C\times 0.9E=CE(1-e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}})

or

0.9=1-e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}}

or

e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}}=1-0.9=0.1

taking log both sides, we get

ln(e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}})=ln(0.1)=ln(\frac{1}{10})

or

-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}=-ln(10)

or

t=75\times 10^6\ \times\ 85\times 10^{-12}\times ln{10}

or

t=14.678\times 10^{-3}s

3 0
3 years ago
During intercourse, Lydia constantly worries whether her partner thinks she is
Misha Larkins [42]
Answer is c spectatoring
6 0
3 years ago
If the distance from a light source triples, how does light intensity change? The intensity will be 3x greater. The intensity wi
Tcecarenko [31]

Answer:

The intensity will be 1/9 as much.

Explanation:

The intensity of the light or any source is inversely related to the square of the distance.

I\alpha \frac{1}{r^{2} }

Now according to the question the distance is increased by three times than,

\frac{I_{2} }{I_{1} }=\frac{r_{1}^{2} }{r_{2}^{2} }

Therefore,

\frac{I_{2} }{I_{1} }=\frac{r_{1}^{2} }{(3r_{1})^{2} }\\\frac{I_{2} }{I_{1} }=\frac{1}{9} \\{I_{2}=\frac{1}{9}{I_{1} }

Therefore the intensity will become 1/9 times to the initial intensity.

3 0
3 years ago
How much work is done in holding a 20 N sack of potatoes while waiting in line at the
Yuki888 [10]

Answer: A

Explanation:

honestly, it sounded the best

8 0
2 years ago
Can someone help on this I'm really stuck
castortr0y [4]
Here, "Wavelength is same for both waves" it is the distance between two crests or two consecutive troughs, so, it is constant for both of them, you can easily figure it out.

In short, Your Answer would be "Wavelength"

Hope this helps!
5 0
3 years ago
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