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erastova [34]
3 years ago
11

Help me plz i'll mark brainliest

Physics
1 answer:
HACTEHA [7]3 years ago
8 0

Answer:

a PDF is what u use to upload an assignment to turn it in to get graded

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A car traveling in a straight line at an initial speed of 8.0 meters per second accelerates uniformly to a speed of 14 meters pe
Whitepunk [10]

The equation we can use here is:

v^2 = v0^2 + 2 a d

where v is final velocity, v0 is intial velocity, a is acceleration and d is distance

 

14^2 = 8^2 + 2 a (44)

<span>a = 1.5 m/s^2</span>

4 0
3 years ago
Read 2 more answers
PLS HELP FIND THE AVREGE KENETIC ENERGY!!
ANEK [815]

Answer: if you gogle it it will tell you the awenser

lanation:

4 0
3 years ago
You pick up a 3.4-kg can of paint from the ground and lift it to a height of 1.8 m. (a) how much work do you do on the can of pa
MariettaO [177]

(a) For the work-energy theorem, the work done to lift the can of paint is equal to the gravitational potential energy gained by it, therefore it is equal to

W=mg\Delta h

where m=3.4 kg is the mass of the can, g=9.81 m/s^2 is the gravitational acceleration and \Delta h=1.8 m is the variation of height. Substituting the numbers into the formula, we find

W=(3.4 kg)(9.81 m/s^2)(1.8 m)=60.0 J


(b) In this case, the work done is zero. In fact, we know from its definition that the work done on an object is equal to the product between the force applied F and the displacement:

W=Fd

However, in this case there is no displacement, so d=0 and W=0, therefore the work done to hold the can stationary is zero.


(c) In this case, the work done is negative, because the work to lower the can back to the ground is done by the force of gravity, which pushes downward. Its value is given by the same formula used in part (a):

W=mg \Delta h=(3.4 kg)(9.81 m/s^2)(-1.8 m)=-60.0 J

8 0
3 years ago
A car is traveling on the highway at 28 m/s The driver sees a tree in the middle of the road and slams on the brakes. The car co
wel

Answer:what are the answer options?

Explanation

3 0
3 years ago
Latitude and longitude are the two coordinates that determine a specific point on the Earth’s surface. How does knowing the loca
DedPeter [7]

Answer:

hey sandra! i hope this will help you!

Explanation:

The geographic coordinate system is a reference system that uses the two angular latitude (north or south) and longitude (east or west) coordinates to determine the positions of the land surface points. These two angular coordinates measured from the center of the Earth are from a spherical coordinate system that is aligned with its axis of rotation. These coordinates are usually expressed in sexagesimal degrees:

Latitude measures the angle between any point and the equator. Latitude lines are called parallel and are circles parallel to the equator on the Earth's surface. Latitude is the distance between any point and Ecuador, measured on the meridian that passes through that point.

• All points located on the same parallel have the same latitude.

• Those who are in the north of Ecuador receive the denomination North (N).

• Those who are in the south of Ecuador receive the denomination South (S).

• It is measured from 0º to 90º.

• The latitude of 0º corresponds to Ecuador.

• The North and South poles have latitude 90º N and 90º S respectively.

The length measures the angle along the equator from any point on Earth. It is accepted that Greenwich in London is length 0 in most modern societies. The lines of length are maximum circles that pass through the poles and are called meridians.

• All points located on the same meridian have the same length.

• Those who are east of Meridian Zero receive the designation East (E).

• Those who are west of Meridian Zero receive the denomination West (O).

• It is measured from 0º to 180º.

• The Greenwich meridian corresponds to the length 0º.

By combining these two angles, the position of any point on the Earth's surface can be expressed.

6 0
3 years ago
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