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Wewaii [24]
3 years ago
7

How can you best describe Periodic Behaviour?

Mathematics
1 answer:
Inessa05 [86]3 years ago
8 0

Answer:

Periodic Behavior consists of insects, like most other living organisms, exhibit cycles of activity that are synchronized with periodic events in their environment. Hatching, molting, foraging for food, courtship, and nest building are all examples of common behaviors that may recur at regular intervals.

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help I will fail math class please help doors for the small cabinets are 11.5 inches long . doors for the large cabinet are 2.3
VARVARA [1.3K]
11.5 * 2.3 = large door size
large door size / 12 = large door size in feet
large door size in feet / 10 = how many large doors can be cut from the board. (you have to round it down if there's a decimal- no 1/2 doors.)
7 0
2 years ago
While in transit, the antitoxin had to stay between 36ºF and 46ºF. The dogsled teams stopped along the route often to warm the a
eimsori [14]
Range is the difference between the largest and the smallest numbers in a given contest

Hence the range
= 46 - 36
= 10 °F
6 0
2 years ago
Jason is playing a trivia game with his friends. At the end of each round, his score updates to the square of 1 less than the pr
mezya [45]

Answer:

8+n^2

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
To eliminate the y terms, you can multiply the first equation by 5 and the second equation by what number?
gladu [14]

Step-by-step explanation:

the second equation should be multiplied by 9

6 0
2 years ago
If a 24-kg mass stretches a spring 15 cm, what mass will stretch the spring 10 cm
natulia [17]

Answer:

<h2>16kg</h2>

Step-by-step explanation:

 This problem is borers on elasticity of materials.

according to Hooke's law,<em> "provided the elastic limit of an elastic material is not exceeded the the extension e is directly proportional to the applied force."</em>

F= ke

where F is the applied force in N

          k is the spring constant N/m

          e is the extension in meters

Given data

mass m= 24kg

extensnion=15cm in meters= \frac{15}{100}= 0.15m

we can solve for the spring constant k

we also know that the force F = mg

assuming g=9.81m/s^{2}

therefore

24*9.81=k*0.15\\235.44=k*0.15\\k=\frac{235.44}{0.15} \\k=1569.6N/m\\

We can use this value of k to solve for the mass that will cause an extension of  10cm= 0.1m

x*9.81=1569.6*0.1\\\\x= \frac{156.96}{9.81} \\\x= 16kg

5 0
3 years ago
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