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4 years ago

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Human activities have had major effects on land, vegetation, streams, ocean, air and even outer space. How can you help protect

Earth’s resources and the environment? Make sure to claim your statement and provide evidence and reasoning.

1 answer:

fiasKO [112]4 years ago

6 0

Answer: you can protect earth’s resources by reducing, reusing, and recycling you can also you can plant a tree!

Explanation:

If you don’t reuse or recycle our planet will be covers in plastic, by planting trees you can help the environment grow

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A galvanic cell at a temperature of 25.0°C is powered by the following redox reaction:

Vlada [557]

<u>Answer:</u> The cell voltage of the given chemical reaction is 2.74 V

<u>Explanation:</u>

For the given chemical reaction:

$Sn^{2+}(aq.)+Ba(s)\rightarrow Ba^{2+}(aq.)+Sn(s)$

Here, gold is getting reduced because it is gaining electrons and nickel is getting oxidized because it is loosing electrons.

<u>Oxidation half reaction:</u> $Ba(s)\rightarrow Ba^{2+}(aq.)+2e^-;E^o_{Ba^{2+}/Ba}=-2.90V$

<u>Reduction half reaction:</u> $Sn^{2+}(aq.)+2e^-\rightarrow Sn(s);E^o_{Sn^{2+}/Sn}=-0.14V$

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

$E^o_{cell}=-0.14-(-2.90)=2.76V$

To calculate the EMF of the cell, we use the Nernst equation, which is:

$E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Sn^{2+}]}{[Ba^{2+}]}$

where,

$E_{cell}$ = electrode potential of the cell = ?V

$E^o_{cell}$ = standard electrode potential of the cell = +2.76 V

n = number of electrons exchanged = 2

$[Ba^{2+}]=5.15M$

$[Sn^{2+}]=1.59M$

Putting values in above equation, we get:

$E_{cell}=2.76-\frac{0.059}{2}\times \log(\frac{1.59}{5.15})\\\\E_{cell}=2.74V$

Hence, the cell voltage of the given chemical reaction is 2.74 V

8 0

4 years ago

A solution has a pH of 4.20. Using the relationship between pH and pOH, what is the concentration of OH−?

frez [133]

Answer : The concentration of $OH^-$ ion is, $1.58\times 10^{-10}M$

Solution : Given,

pH = 4.20

First we have to calculate the pOH.

As we know that,

$pH+pOH=14$

$pOH=14-pH$

$pOH=14-4.20$

$pOH=9.8$

Now we have to calculate the concentration of $OH^-$ ion.

$pOH=-\log [OH^-]$

$9.8=-\log [OH^-]$

$[OH^-]=1.58\times 10^{-10}M$

Therefore, the concentration of $OH^-$ ion is, $1.58\times 10^{-10}M$

4 0

3 years ago

Read 2 more answers

Consider the differences between organic and inorganic

ZanzabumX [31]

Answer: organic compounds has made up of organic materials inorganic compounds are made up of inorganic materials.

organic compounds make good electrolytes

inorganic compounds exhibit ionic bonding

organic compounds lower melting points

Explanation:

6 0

4 years ago

Forensic science is the application of science to what field?

adell [148]

B.) Criminal Justice

8 0

4 years ago

Read 2 more answers

What mass of water will change its temperature by 3.0 0C when 525 J of heat is added to it? The specific heat of water is 4.184

pav-90 [236]

Answer:

Mass of water = 41.8 g

Explanation:

Given data:

Mass of water = ?

Change in temperature = 3.0 °C

Specific heat capacity = 4.184 j/g.°C

Heat absorbed = 525 j

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 3.0°C

Now we will put the values in formula.

525 J = m × 4.184 j/g.°C × 3.0°C

525 J = m × 12.552 j/g

m = 525 J/ 12.552 j/g

m = 41.8 g

4 0

3 years ago