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Rzqust [24]
3 years ago
14

16x16+14-99x8= First to get it right gets my hulu account NO CHEATING WITH A CACULATOR

Mathematics
2 answers:
vova2212 [387]3 years ago
5 0

Answer:

16x16+14−99x8

=16x16+14+−99x8

Answer- =16x16−99x8+14

sooo its -522

Step-by-step explanation:

hope this helps! :)

iragen [17]3 years ago
3 0

Step-by-step explanation:

16×16+14-99×8= -552

steps := (4^2.4^2) + 4 -11×3×3×8

= (4^2+2 ) +4 - (33)×3×8

= 4^4 +4 -33×24

=256+4-792

=270-792

= -522

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Use matrix addition to solve this equation: B + 15 −7 4 0 1 2 = 1 2 12 4 0 2 b11 = b12 = b13 = b21 = 4 b22 = −1 b23 = 0
Arada [10]

Answer:

b_{11}=-14,b_{12}=9,b_{13}=8,b_{21}=4,b_{22}=-1,b_{23}=0

Step-by-step explanation:

The given matrix addition is

B+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}

We need to find the elements of matrix B.

Let B=\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}

Substitute the value of matrix.

\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}

After addition of two matrix we get

\begin{bmatrix}b_{11}+15&b_{12}-7&b_{13}+4\\ b_{21}+0&b_{22}+1&b_{23}+2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}

On equating both sides.

b_{11}+15=1\Rightarrow b_{11}=-14

b_{12}-7=2\Rightarrow b_{12}=9

b_{13}+4=12\Rightarrow b_{13}=8

b_{21}+0=4\Rightarrow b_{21}=4

b_{22}+1=0\Rightarrow b_{22}=-1

b_{23}+2=2\Rightarrow b_{23}=0

Therefore, the elements of matrix B are b_{11}=-14,b_{12}=9,b_{13}=8,b_{21}=4,b_{22}=-1,b_{23}=0.

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3 years ago
(7x-3) ( 11y+5) what’s the value of x
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11y + 5 = 60

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Step-by-step explanation:

plz mark brainest

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3 years ago
The Radius of a circle is 5 cm. Find the area of the circle, correct to one decimal place.
lorasvet [3.4K]

Answer:

78.5

Step-by-step explanation:

r^{2}x3.14 (pie)

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5x5=25

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Write the equation of the line in point-slope form that goes through the points (0, 1) and (2, 7)
laiz [17]

Answer:

point - slope form

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Step-by-step explanation:

<u><em>step(i):-</em></u>

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The slope of the line

     m = \frac{y_{2}-y_{1}  }{x_{2} -x_{1} }

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<u><em>Step(ii):-</em></u>

point -slope form

   y - y₁ = m(x-x₁)

Equation of the straight line passing through the point (0,1) and having slope 'm' = 3

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  y -1 = 3x

 3x - y +1=0

Equation of the straight line passing through the point (0,1) and having slope 'm' = 3 is 3x -y +1=0

4 0
2 years ago
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