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umka21 [38]
3 years ago
6

Samuel takes 5 coolers to his basketball game. Each cooler holds 9 liters of water. How many liters of water altogether did he t

ake to the game?
Mathematics
1 answer:
Brrunno [24]3 years ago
4 0
5*9=45



Hope this helped
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The total cost should be around 19.20
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Please Help this is Due in 1 hour and I really dont understand any of this. (Question in Image)
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Step-by-step explanation:

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2 years ago
Out of 22 players in a team, 10 of them have an average height of 1.50m while another 10 have an average height of 1.48m. The re
Sonja [21]

Answer:

1.5 meters

Step-by-step explanation:

We know that the sum of all of the data in a set = average * number of data.

Therefore, the sum of the first 10 is 1.5 * 10 = 15 meters, the sum of the second 10 is 1.48 * 10 = 14.8 meters and the sum of the last 2 is 1.6 * 2 = 3.2 meters for a total of 15 + 14.8 + 3.2 = 33 meters. This means that the mean is 33 / 22 = 1.5 meters.

6 0
3 years ago
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In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
What is the slope of a line that is parallel to the line y = x + 2?
Sauron [17]

Answer:

m = - 1

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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