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masha68 [24]
3 years ago
8

What is the midpoint of a line segment with the end points (-4,-3) and (7,-5)

Mathematics
1 answer:
iVinArrow [24]3 years ago
4 0

Midpoint formula is ((\frac{x₁+x₂}{2},\frac{y₁+y₂}{2})

So your equation would be set up as ((\frac{-4+7}{2},\frac{-3+-5}{2})

Which reduces down to ((\frac{3}{2},\frac{-8}{2})

And your answer after dividing is (1.5,-4)

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Differentiate Functions of Other Bases In Exercise, find the derivative of the function.
WARRIOR [948]

Answer:

\dfrac{dy}{dx} =\dfrac{2 x + 6}{ \log{\left (10 \right )}\left(x^{2} + 6 x\right)}

Step-by-step explanation:

given

y = \log_{10}{(x^2+6x)}

using the property of log \log_ab=\frac{log_cb}{log_ca}, and if c =e,\log_ab=\frac{ln{b}}{ln{a}}, we can rewrite our function as:

y = \dfrac{\ln{\left (x^{2} + 6 x \right )}}{\ln{\left (10 \right )}}

now we can easily differentiate:

\dfrac{dy}{dx} = \dfrac{1}{\ln{10}}\left(\dfrac{d}{dx}(\ln{(x^{2} + 6x)})\right)

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\dfrac{dy}{dx} =\dfrac{2 x + 6}{ \log{\left (10 \right )}\left(x^{2} + 6 x\right)}

This is our answer!

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Set a different numbers that give a mean of 17.25
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Here is a set of 5 numbers that give a mean of 17.25.

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x=\frac{-23+/- \sqrt{23^2-4(2)(-19)} }{2(2)}
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x=\frac{-23+ \sqrt{377} }{4} or \frac{-23- \sqrt{377} }{4}
7 0
3 years ago
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