Answer:
x1, x2 = 4.74 , -2.74
Step-by-step explanation:
To find the roots of a quadratic function we have to use the bhaskara formula
ax^2 + bx + c
x^2 - 2x - 13
a = 1 b = -2 c = -13
x1 = (-b + √ b^2 - 4ac)/2a
x2 =(-b - √ b^2 - 4ac)/2a
x1 = (2 + √ (2^2 - 4 * 1 * (-13)))/2 * 1
x1 = (2 + √ (4 + 52)) / 2
x1 = (2 + √ 56 ) / 2
x1 = (2 + 7.48) / 2
x1 = 9.48 / 2
x1 = 4.74
x2 = (2 - √ (2^2 - 4 * 1 * (-13)))/2 * 1
x2 = (2 - √ (4 + 52)) / 2
x2 = (2 - √ 56 ) / 2
x2 = (2 - 7.48) / 2
x2 = -5.48 / 2
x2 = -2.74
Answer:
Acute isoceles
Step-by-step explanation:
Two base angles of the triangle are equal making it isosceles
The top angle is less than 90° making it an acute angle
The answer is 1,4 therefore y = 1x - 4
Answer:
The slope of Function A is greater than the slope of function B while the y-intercept of Function B is greater than the y-intercept of function A.
Step-by-step explanation:
Function A is f(x) = 5x + 2
The slope is 5 and the y-intercept is (0, 2).
Function B. The slope is (5-2) / (0- -1) = 3.
also (8-5) / (1 - 0) = 3
The slope is 3.
The y-intercept is at (0, 5) because one point on the graph is (0, 5).
Refer to the diagram below
If we draw a line that connects the center of rotation to one of the points, say point N, and take this line as the 0° position, then we need three 'turn' of 90° to get to 270°.
Coordinate of N' (-3, 4)
Coordinate of M' (-9, 5)
