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andre [41]
3 years ago
6

A beaker of negligible heat capacity contains 456 g of ice at -25.0°C. A lab technician begins to supply heat to the container a

t the rate of 1000 J/min. How long after starting will it take before the temperature starts to rise above 0°C
Physics
1 answer:
Scorpion4ik [409]3 years ago
4 0

Answer:

176 min

Explanation:

456 g = .456 kg

Specific heat of ice s = 2093 J kg⁻¹

Heat required to raise the temperature by 25 degree

= mass x specific heat x rise in temperature.

= .456 x 2093 x 25

=23860 J

Heat required to melt the ice to make water at zero degree

= mass x latent heat

= .456 x 334 x 10³

=152304 J

Total heat required = 152304 + 23860 = 176164 J .

Time Required = Heat required / rate of supply of heat

= 176164 / 1000

176.16 min

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 Mass have no effect for the projectile motion and  u want to know the  height "h"   
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horizontal component of velocity = 12 cos 61
now for the vertical motion ;               
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where
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u = initial vertical component of velocity 
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6 0
3 years ago
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Answer:

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It takes 500 J of work to compress a spring 10 cm. What is the force constant of the spring? (b) When a 3.0 kg block is pushed a
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Answer:

Explanation:

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500 = 5 x 10⁻³ k ,

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b )

k = 4.5 x 10¹ = 45 N/m

Stored energy = 1/2 k x² = .5 x 45 x 8² x 10⁻⁴ =1440 x 10⁻⁴ J

This energy gets dissipated by friction .

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There are different types of nerve endings, particularly the ones responsible to detect pain, and temperature are the free nerve endings.

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