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3 years ago

Someone help plzz :))

Physics

2 answers:

Aleks04 [339]3 years ago

5 0

The first one is phytoplankton:))

Luden [163]3 years ago

3 0

How did you take a picture?

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A 56 kg sprinter, starting from rest, runs 49 m in 7.0 s at constant acceleration.what is the sprinter's power output at 2.0 s,

alexgriva [62]

The sprinter is in uniform accelerated motion, and its initial velocity is zero, so the relationship betwen space (S) and time (t) is
$S= \frac{1}{2} a t^2$
where a is the acceleration. Using the data of the problem, we can find a:
$a= \frac{2S}{t^2} = \frac{2 \cdot 49 m}{(7.0 s)^2} =2.0 m/s^2$
So now we can solve the 3 parts of the problem.

a) power output at t=2.0 s
The velocity at t=2.0 s is
$v(t)=at=(2.0 m/s^2)(2.0 s)=4.0 m/s$

the kinetic energy of the sprinter is
$K= \frac{1}{2} mv^2= \frac{1}{2}(56 kg)(4.0 m/s)^2=448 J$

and so the power output is
$P= \frac{E}{t} = \frac{448 J}{2.0 s} =224 W$

b) power output at t=4.0s
The velocity at t=4.0 s is
$v(t)=at=(2.0 m/s^2)(4.0 s)=8.0 m/s$

the kinetic energy of the sprinter is
$K= \frac{1}{2} mv^2= \frac{1}{2}(56 kg)(8.0 m/s)^2=1792 J$

and so the power output is
$P= \frac{E}{t} = \frac{1792 J}{4.0 s} =448 W$

c) Power output at t=6.0 s
The velocity at t=2.0 s is
$v(t)=at=(2.0 m/s^2)(6.0 s)=12.0 m/s$

the kinetic energy of the sprinter is
$K= \frac{1}{2} mv^2= \frac{1}{2}(56 kg)(6.0 m/s)^2=4032 J$

and so the power output is
$P= \frac{E}{t} = \frac{4032 J}{6.0 s} =672 W$

8 0

2 years ago

A piece of steel expands 10 cm when ur is heated from 20 to 50 degrees Celsius. How much would it expand if it was heated from 2

faltersainse [42]

The steel would expand by 4. 8 * 10^-3 cm

<h3>How to determine the linear expansion</h3>

The change in length ΔL is proportional to length L. It is dependent on the temperature, substance, and length.

Using the formula:

ΔL= α LΔT

where ΔL is the change in length L = 10cm

ΔT is the change in temperature = 60° - 20° = 40° C

α is the coefficient of linear expansion = 1.2 x 10^-5 °C

Substitute into the formula

ΔL = $1.2 * 10^-5 * 10 * 40$

ΔL = $4.8 * 10 ^-3$ cm

Therefore, the steel would expand by 4. 8 * 10^-3 cm

Learn more about linear expansion here:

brainly.com/question/14325928

#SPJ1

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1 year ago

Suppose a rock is hoisted up with a rope. The rock experiences 10 N of tension force upward and 10 N of gravitational force down

nika2105 [10]

False. Since the forces are pulling in equal and opposite directions, the net force is 0.

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3 years ago

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Astronomers believe that cosmic background radiation formed:

mr_godi [17]

The assumption that the cosmic microwave background
is the remnant of the environment at the time of the big bang
or very shortly after it explains very well what we observe now.
So it is the current prevailing theory. "Believe" is not involved.

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2 years ago

Explain How can you tell that river water is suspension ?

andreev551 [17]

Answer:

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At the point when vitality levels are high, huge rocks and stones can be moved. Vitality levels are generally higher close to a waterway's source, when its course is steep and its valley slender. Vitality levels rise considerably higher in the midst of flood.

At the point when vitality levels are low, just little particles can be moved (assuming any). Vitality levels are most reduced when speed drops as a waterway enters a lake or ocean (at the mouth).

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3 years ago