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Karo-lina-s [1.5K]
3 years ago
11

A bowl contains 8 chips: 4 blue and 4 red. Three chips are drawn at random and without replacement from a bowl. What is the prob

ability that all three chips chosen?
a. 1/4
b. 1/8
c. 1/10
d. 1/13
e. 1/15
Mathematics
1 answer:
PIT_PIT [208]3 years ago
8 0

Answer:

the probability that 3 blue chips ( or red chips) are chosen is P(X=3) = 1/14

Step-by-step explanation:

Since the X= choosing  x blue chips, then P(X) follows an hypergeometric distribution , when sampling is done without replacement

P(X=x) = (C,x) * (N-C , n-x) /( N ,n)

where ( ) represents combinations then

N= population size = 8 chips

n = sample size = 3 chips

C = number of blue chips = 4 chips

x= number of blue chips that are chosen = 3 blue chips

replacing values

P(X=3) = (4,3) * (8-4 , 3-3) /( 8 ,3) = (4,3) * (4 , 0 ) /( 8 ,3) = 4 * 1  / [ 8!/(3!*5!) ] =

4*3!*5! /8! = 1/14

P(X=3) = 1/14

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If the perimeter of a square is 20, find the length of a diagonal
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Answer:

7.07

Step-by-step explanation:

<h2><u>Length</u></h2>

a square has equal length on each side

hence is the perimeter is 20 it means that :

each side is 20/4 = 5

we can make a diagonal line which create 3 right angled triangles

2 sides of the triangle are 5 , this is the base and the height

to find the length we can make use of the Pythagoras theorem

c^2 = a^2 + b^2

c is the hypotenuse ( the diagonal;)

a and b are the opposite and adjacent

hence :

c^2 = 5 ^2 + 5^2

c^2 = 50

c = \sqrt{50}

c = 7.071

to 3sf

<h3><u>diagonal length  = 7.07</u></h3>

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A jeweler wants to make 14 grams of an alloy that is precisely 75% gold.. The jeweler has alloys that are 25% gold, 50% gold, &a
Goryan [66]

Given that the jeweler has alloys that are 25% gold, 50% gold, and 82% gold.

As he wants to make 14 grams of an alloy by adding two different alloys that is precisely 75% gold, so one alloy must have a percentage of gold more than 75%.

One alloy is 82% gold and, the second can be chosen between 25% gold, 50% gold, so there are two cases.

Case 1: 82% gold + 50% gold

Let x grams of 82% gold and y  grams of 50% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 50% of y

\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times y \\\\

\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times (14-x)  [as x+y=14]

\Rightarrow 75 \times 14 = 82 \times x + 50 \times (14-x)  \\\\\Rightarrow 75 \times 14 = 82 \times x + 50 \times14-50\times x \\\\\Rightarrow 75 \times 14 = 32 \times x + 50 \times14 \\\\\Rightarrow 32 \times x =75 \times 14 - 50 \times14 \\\\

\Rightarrow x =(25 \times 14)/32=10.9375 grams

and y = 14-x= 14-10.9375=3.0625 grams.

Hence, 10.9375 grams of 82% gold and 3.0625  grams of 50% gold added to make 14 grams of 75% gold.

Case 2: 82% gold + 25% gold

Let x grams of 82% gold and y  grams of 25% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 25% of y

\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times y \\\\\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times (14-x) \\\\ \Rightarrow 75 \times 14 = 82 \times x + 25 \times (14-x)  \\\\\Rightarrow 75 \times 14 = 82 \times x + 25 \times14-25\times x \\\\\Rightarrow 75 \times 14 = 57 \times x + 25 \times14 \\\\\Rightarrow 57 \times x =75 \times 14 - 25 \times14 \\\\

\Rightarrow x =(50 \times 14)/57=12.28 grams

and y = 14-x= 14-12.28=1.72 grams.

Hence, 12.28 grams of 82% gold and 1.72  grams of 50% gold added to make 14 grams of 75% gold.

3 0
2 years ago
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