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4 years ago

A person hits a tennis ball with a mass of 0.058 kg against a wall.

Physics

1 answer:

Alla [95]4 years ago

6 0

Explanation:

Mass of the ball, m = 0.058 kg

Initial speed of the ball, u = 11 m/s

Final speed of the ball, v = -11 m/s (negative as it rebounds)

Time, t = 2.1 s

(a) Let F is the average force exerted on the wall. It is given by :

$F=\dfrac{m(v-u)}{t}$

$F=\dfrac{0.058\times (11-(-11))}{2.1}$

F = 0.607 N

(b) Area of wall, $A=3\ m^2$

Let P is the average pressure on that area. It is given by :

$P=\dfrac{F}{A}$

$P=\dfrac{0.607\ N}{3\ m^2}$

P = 0.202 Pa

Hence, this is the required solution.

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A 328-kg car moving at 19.1 m/s in the x direction hits from behind a second car moving at 13.0 m/s in the same direction. If th

Jet001 [13]

Answer:

14.04 m/s

Explanation:

To find the velocity of the first car after the collision, we can use the equation of conservation of momentum:

m1v1 + m2v2 = m1'v1' + m2'v2'

We have the following data:

m1 = m1' = 328,

m2 = m2' = 790,

v1 = 19.1,

v2 = 13,

v2' = 15.1.

Using this data, we can find v1' (final velocity of the first car):

328 * 19.1 + 790 * 13 = 328 * v1' + 790 * 15.1

16534.8 = 328 * v1' + 11929

328 * v1' = 4605.8

v1' = 14.04 m/s

3 0

3 years ago

In a collision an object experiences impulses , this impulse can be determined by

astraxan [27]

In a collision an object experiences impulses, this impulse can be determined by the product of net force exerted upon it in the specific course of time.

Explanation:

An object experiences impulse due to the force exerted upon it in a particular time period.

i.e.

$\text {Impulse }=F \times \Delta t$

Where,

F - Force acted upon the object

$\Delta t$ - time interval for which the force act

According to the definition of Impulse, it is the integral of force (F) that acts upon any object over a time interval ∆t. It produces an equivalent change in the momentum and that too in the same direction as of the applied force (F).

Therefore, in order to find the impulse on an object, we have to find the force acted on it in a specific time interval.

8 0

3 years ago

a 10. kg ball thrown into the air. it is going 3.0 m/s when thrown. how much potential energy will it have at the top?

Sever21 [200]

Answer:

45 j

Explanation:

At the top, the KE will have been converted to PE

KE = 1/2 mv^2 =PEat-top = 1/2 10 *3^9 = 45 j

6 0

2 years ago

How many neutrons does element X have if its atomic number is 43 and its mass number is 164?

Drupady [299]

Hello,
The mass number is protons+neutrons=mass number. In this case, we have protons+nuetron=164.The atomic number is simply the number of protons so we have 43+neutrons=164. Subtracting 43 from both sides we get nuetrons=121. Hope this helps!

6 0

3 years ago

Read 2 more answers

1. Use the periodic table to determine which of the following groups of elements would have properties most similar to arsenic (

Sliva [168]

Answer:

Explanation:

The correct answer would be option D.

Gallium (Ga) , germanium (Ge) , selenium (Se) , and arsenic (AS) all belong to the same group of elements referred to as the transition elements. The transition elements have partially-filled d orbital, a feature that confers some characteristic properties on the elements or their ions. These properties include:

variable oxidation state of
formation of colored ions and compounds
catalytic property
paramagnetic compounds
etc.

6 0

3 years ago