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2 years ago

If asked to describe a wave, you could say waves are the

2 answers:

7 0

Wave is a disturbance that transfer energy from one point to another without permanent deformation of the transferring medium.

serious [3.7K]2 years ago

3 0

Good evening Carolina

You could say waves are the continuous transmission of energy from one location to the next.

I hope that's help:)

You might be interested in

in a thermal power plant, heat from the flue gases is recovered in (A) chimney (B) de-super heater (C) economizer (D) condenser

Volgvan

Answer:

(A)chimney

Explanation:

bc all the smoke is going into the chimney

8 0

3 years ago

Parallel Circuits:

Ber [7]

Answer:

D.)

Explanation:

the current separates on each branch according to the resistance it experience.

8 0

3 years ago

A cylindrical tank of methanol has a mass of 70 kg and a volume of 75 L. Determine the methanol’s weight, density, and specific

dem82 [27]

Answer:

Weight=686.7N, $\rho=933kg/m^{3}$ , S.G.=0.933, F=17.5N

Explanation:

So, the first value the problem is asking us for is the weight of methanol. (This is supposing there is a mass of methanol of 70kg inside the tank). We can find this by using the formula:

W=mg

so we can substitute the data the problem provided us with to get:

$W=70kg(9.81m/s^{2})$

which yields:

W=686.7N

Next, we need to find the density of methanol, which can be found by using the following formula:

$\rho=\frac{m}{V}$

we know the volume of methanol is 75L, so we can convert that to $m^{3}$ like this:

$75L*\frac{0.001m^{3}}{1L}=0.075m^{3}$

so we can now use the density formula to find our the methanol's density, so we get:

$\rho=\frac{m}{V}$

$\rho=\frac{70kg}{0.075m^{3}}$

$\rho=933.33kg/m^{3}$

Next, we can us these values to find the specific gravity of methanol by using the formula:

$S.G.=\frac{\rho_{sample}}{\rho_{H_{2}O}}$

when substituting the known values we get:

$S.G.=\frac{933.33kg/m^{3}}{1000kg/m^{3}}$

so:

S.G.=0.933

We can now find the force it takes to accelerate this tank linearly at $0.25m/s^{2}$

F=ma

$F=(70kg)(0.25m/s^{2})$

F=17.5N

6 0

3 years ago

A 100 W incandescent lightbulb emits about 5 W of visible light. (The other 95 W are emitted as infrared radiation or lost as he

frutty [35]

Answer:

n = 1.89 x 10¹⁹ photons/s

Explanation:

given,

Power of bulb = 100 W

Visible light = 5 W

wavelength of the visible light = 600 nm

number of photons emitted per second

using formula of wavelength

$\lambda = \dfrac{c}{\nu}$

$\nu= \dfrac{c}{\lambda}$

$\nu= \dfrac{3 \times 10^8}{600 \times 10^{-9}}$

$\nu=5 \times 10^{14}\ Hz$

energy of photon

U = h υ

U = 6.63 x 10⁻³⁴ x 4 x 10¹⁴

U = 2.65 x 10⁻¹⁹ J

number of photon

$n = \dfrac{P}{U}$

$n = \dfrac{5}{2.65 \times 10^{-19}}$

n = 1.89 x 10¹⁹ photons/s

6 0

2 years ago

A more realistic car would cause the wheels to spin in a manner that would result in the ground pushing it forward with a consta

Artist 52 [7]

Answer:

3 seconds

Explanation:

To solve this problem, we have to find the acceleration of the car.

Acceleration is given as:

a = (v - u) / t

Where v = final velocity

u = initial velocity

t = time taken.

From the question,

u = 0 m/s

v = 31 mph = 13.86 m/s

t = 1.5 seconds

Acceleration, a, will be:

a (13.86 - 0) / 1.5

a = 13.86 / 1.5

a = 9.24 m/s²

We are told that this kind of car operates with constant force. This means it operates with constant acceleration (since force and acceleration are directly proportional)

Therefore, when the final velocity of the car is 62 mph (27.72 m/s), time taken is:

a = (v - u) / t

=> t = (v - u) / a

t = (27.72 - 0) / 9.24

t = 3 seconds

It will take the car 5 seconds to go from zero to 62 mph.

8 0

3 years ago