How many lead (Pb) atoms will be generated when 5.38 moles of ammonia react according to the following equation: 3PbO+2NH3→3Pb+N

Question

3 years ago

12

2+3H2O?
A) 1.62 × 10^24
B) 4.86 × 10^23
C) 2.43 × 10^24
D) 4.86 × 10^24

2 answers:

Schach [20] · Answer 1 · 2022-04-09T00:08:35+03:00

8 0

Answer:

4.86×10^23 molecule of Pb

Explanation:

jasenka [17] · Answer 2 · 2022-04-08T21:43:29+03:00

Answer:

4.86×10^23 molecule of Pb

Explanation:

Based on that equation, for every 2 moles of ammonia, you get 3 moles of lead.

So:

2 mol NH3/ 3 mol Pb

Using this ratio we can find the amounts of either molecule. Given 5.38 mol NH3:

(5.38 NH3)(3 Pb/ 2 NH3) = (5.38)(3/2) mol Pb = 8.07 mol Pb

Then, we just need to use Avagadro's number to get the number of molecules.

(8.07)(6.02×10^23) = 4.86×10^23 molecule of Pb