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VladimirAG [237]
3 years ago
12

How many lead (Pb) atoms will be generated when 5.38 moles of ammonia react according to the following equation: 3PbO+2NH3→3Pb+N

2+3H2O?
A) 1.62 × 10^24
B) 4.86 × 10^23
C) 2.43 × 10^24
D) 4.86 × 10^24
Chemistry
2 answers:
Schach [20]3 years ago
8 0

Answer:

4.86×10^23 molecule of Pb

Explanation:

jasenka [17]3 years ago
4 0

Answer:

4.86×10^23 molecule of Pb

Explanation:

Based on that equation, for every 2 moles of ammonia, you get 3 moles of lead.

So:

2 mol NH3/ 3 mol Pb

Using this ratio we can find the amounts of either molecule. Given 5.38 mol NH3:

(5.38 NH3)(3 Pb/ 2 NH3) = (5.38)(3/2) mol Pb = 8.07 mol Pb

Then, we just need to use Avagadro's number to get the number of molecules.

(8.07)(6.02×10^23) = 4.86×10^23 molecule of Pb

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Answer:

A

Explanation:

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Answer:

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Explanation:

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Answer:

The right solution according to the question is provided below.

Explanation:

According to the question,

(a)

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      = \frac{2048}{300}

      = 6.826 \ mg/L

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     = 1.674 \ mg/L

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(b)

The time reach minimum DO:

tc = \frac{1}{(kr-kd)} ln{(\frac{0.76}{0.61} )[1-\frac{1.674(0.76-0.61)}{0.61\times 6.453} ]}

   = \frac{1}{0.15}\times ln \ 1.158

By putting the values of log, we get

   = 0.973 \ days

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Answer:

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