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emmasim [6.3K]
3 years ago
10

I need help ASAP please!​

Chemistry
1 answer:
Dimas [21]3 years ago
7 0

Answer:

The mass is 12.0107 but it rounds up to 12

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What happens to the ratio of oxygenated hbo2(aq) to deoxygenated hb(aq), i.e. , when there is a high pressure of oxygen, po2(g),
maw [93]

The chemical equilibrium representing the reaction of hemoglobin with oxygen is,

Hb (aq) + O_{2}(g)  HbO_{2}(aq)

In the lungs, where the partial pressure of oxygen is high, the above equilibrium shifts towards the products according to the LeChattelier's principle, as the pressure of one of the reactants is increased. This leads to the formation of more oxyhemoglobin.

In the cells, where the partial pressure of oxygen is low, the equilibrium shifts towards left that is hemoglobin.

Therefore the ratio of oxyhemoglobin to hemoglobin increases as the partial pressure of oxygen is high in the lungs.

4 0
4 years ago
(ILL GIVE 100 POINTS AND EDIT IT AND MARK BRAINLIEST) Examine the diagram of the cell cycle. Which label identifies the stage in
mr_godi [17]

Answer:

where is diagram. sorry.

7 0
3 years ago
Read 2 more answers
A sample of gasoline has a mass of 595.0 lb and a volume of 14.0 ft^3. What is its specific gravity?
Sedbober [7]

Explanation:

The given data is as follows.

            mass of gasoline = 595.0 lb

            volume of gasoline = 14.0 ft^{3}

As it is known that density is the amount of mass of a substance divided by its volume.

So, density of gasoline will be as follows.

                Density = \frac{mass}{volume}

                              = \frac{595.0 lb}{14.0 ft^{3}}

                              = 42.5 lb/ft^{3}

As, 1 lb = 0.4536 kg and 1 ft = 0.3048 m. Now, putting these values into the above equation (1) as follows.

                       Density = 42.5 lb/ft^{3}

                                     = 42.5 \times \frac{0.4536 kg}{(0.3048 m)^{3}}

                                     = 680.792 kg/m^{3}    

                                     = 680.8 kg/m^{3} (approx)

Density of water is 1000 kg/m^{3}. To measure specific gravity of gasoline, the formula will be as follows.

               specific gravity of gasoline = \frac{\text{density of gasoline}}{\text{density of water}}    

                                         = \frac{680.8 kg/m^{3}}{1000 kg/m^{3}}

                                         = 0.681

Thus, we can conclude that the specific gravity of gasoline is 0.681.

4 0
4 years ago
How many moles are in 5.67x10^24 atoms of RbCl?
Mademuasel [1]

Answer:

<h2>9.42 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{5.67 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 9.418604...

We have the final answer as

<h3>9.42 moles</h3>

Hope this helps you

4 0
3 years ago
What is the final volume of a 400 ML sample that is subjected To a temperature change from 22 Celsius to 30 Celsius in a pressur
bija089 [108]

Answer:

The answer to your question is  V2 = 867.3 mL

Explanation:

Data

Volume 1 = V1 = 400 ml

Temperature 1 = T1 = 22°C

Pressure 1 = P1 = 760 mmHg

Volume 2 = V2 = ?

Temperature 2 = T2 = 30°C

Pressure 2 = P2 = 360 mmHg

Process

1.- Convert Celsius to Kelvin

T1 = 22 + 273 = 295°K

T2 = 30 + 273 = 303°K

2.- Use the Combined gas law

              P1V1/T1 = P2V2/T2

- Solve for V2

            V2 = P1V1T2 / T1P2

- Substitution

            V2 = (760 x 400 x 303) / (295 x 360)

- Simplification

            V2 = 92112000 / 106200

-Result

            V2 = 867.3 mL

8 0
3 years ago
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