Answer:
pH = 10.11
Explanation:
Hello there!
In this case, since it is possible to realize that this base is able to acquire one hydrogen atom from the water:
We can therefore set up the corresponding equilibrium expression:
![Kb=\frac{[C_{18}H_{21}NO_4H^+][OH^-]}{[C_{18}H_{21}NO_4]}](https://tex.z-dn.net/?f=Kb%3D%5Cfrac%7B%5BC_%7B18%7DH_%7B21%7DNO_4H%5E%2B%5D%5BOH%5E-%5D%7D%7B%5BC_%7B18%7DH_%7B21%7DNO_4%5D%7D)
Which can be written in terms of the reaction extent, 
:
Thus, by solving for we obtain:
However, since negative solutions are now allowed, we infer the correct is 0.0001285 M; thus, the pOH can be computed:
And finally the pH:
Best regards!
You have the stoichiometric equation. This tells you unequivocally that an
18
⋅
g
mass of water, 1 mole, reacts with a
56.07
⋅
g
mass of quicklime to form a
74.09
⋅
g
mass of slaked lime.
If you don't from where I am getting these numbers, you should know, and someone will be willing to elaborate.
Here, you have formed
6.21
⋅
m
o
l
of quicklime which requires stoichiometric lime AND water. And thus you need a mass of
6.21
⋅
m
o
l
×
18.01
⋅
g
⋅
m
o
l
−
1
water
≅
88
⋅
g
.
In practice, of course I would not weigh out this mass. I would just pour
100
−
200
⋅
m
L
of water into the lime.
Answer:
A buffer solution is a mixture of two pair salts to maintain a stable pH.
Explanation:
This mixture is made always with a complementary pair of salts (one acid an another basic).
Example:
Acetic Acid (CH3COOH) and Sodium Acetate (NaH3COO).
So when you add a little bit more acid to this mixture, the basic part of the buffer, in this case the Sodium Acetate, will neutralize it and the pH will remain the same.
On the other hand, if the mixture receives some basic substance, the acid part of the buffer, the acetic acid, will neutralize it, so again the pH will remain the same.
Answer:
B) a substance's color and odor changed Explanation: A signal that a chemical change has occurred is when its odor (its smell) or its appearance has changed.
