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2 years ago

How many neutrons does the isotope lithium have A.) 3 B.) 5 C.) 8 D.) 4

Chemistry

2 answers:

Fantom [35]2 years ago

6 0

The answer is D they have 4 neutrons

Galina-37 [17]2 years ago

6 0

The answer is D) … they have 4

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of the following warnings, which one refers to a chemical property of a substance? fragile flammable handle with care shake well

coldgirl [10]

Flammable is ur answer

6 0

3 years ago

Which objects cannot be observed in detail without a microscope?

Sonbull [250]

The objects which cannot be observed in detail without a microscope

include the following:

Red blood cell

Bacterium

<h3>What is a Microscope?</h3>

A microscope is an instrument which is used to view smaller objects such as

microbe,cells, tissues etc. This instrument is used in viewing the different

cells found in the body as they can't be seen with the eye.

The remaining options which can be seen with the eyes don't require

the use of microscopes.

Read more about Microscope here brainly.com/question/25268499

3 0

2 years ago

I2(g) + Cl2(g)2ICl(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 1.62 mol

galina1969 [7]

Answer:

The change in entropy of the surrounding is -146.11 J/K.

Explanation:

Enthalpy of formation of iodine gas = $\Delta H_f_{(I_2)}=62.438 kJ/mol$

Enthalpy of formation of chlorine gas = $\Delta H_f_{(Cl_2)}=0 kJ/mol$

Enthalpy of formation of ICl gas = $\Delta H_f_{(ICl)}=17.78 kJ/mol$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]$

For the given chemical reaction:

$I_2(g)+Cl_2(g)\rightarrow 2ICl(g),\Delta H_{rxn}=?$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(2\times \Delta H_f_{(ICl)})]-[(1\times \Delta H_f_{(I_2)})+(1\times \Delta H_f_{(Cl_2)})]$

$=[2\times 17.78 kJ/mol]-[1\times 0 kJ/mol+1\times 62.436 kJ/mol]=-26.878 kJ/mol$

Enthaply change when 1.62 moles of iodine gas recast:

$\Delta H= \Delta H_{rxn}\times 1.62 mol=(-26.878 kJ/mol)\times 1.62 mol=-43.542 kJ$

Entropy of the surrounding = $\Delta S^o_{surr}=\frac{\Delta H}{T}$

$=\frac{-43.542 kJ}{298 K}=\frac{-43,542 J}{298 K}=-146.11 J/K$

1 kJ = 1000 J

The change in entropy of the surrounding is -146.11 J/K.

4 0

3 years ago

devlian [24]

The answer is A because I did this before

8 0

2 years ago

Read 2 more answers

What is the energy of a light wave with a frequency of 9.8 x 10^20 Hz?

Wewaii [24]

Answer:

Regions of the Electromagnetic Spectrum

Wavelength (m)Frequency (Hz)Radio> 1 x 10-1< 3 x 109Microwave1 x 10-3 - 1 x 10-13 x 109 - 3 x 1011Infrared7 x 10-7 - 1 x 10-33 x 1011 - 4 x 1014Optical4 x 10-7 - 7 x 10-74 x 1014 - 7.5 x 1014

7 0

3 years ago