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Marta_Voda [28]
3 years ago
8

A student claims that if she wanted to make a solution quickly, she should use small pellets instead of powder along with heatin

g and stirring. Do you agree or disagree with the student's claim? Answer using CER format. PLS HELP I’m a little confused and don’t know what to put.
Chemistry
1 answer:
torisob [31]3 years ago
4 0

Answer:

<em>I disagree with the student's claim</em>

<em></em>

Explanation:

<em>From basic chemistry, the rate of chemical reaction increases with an increased surface area.</em>

<em>This simply means that a powdered substance will react faster than a small pellet of the same substance.</em>

Let us break this down further. The pellet has a smaller exposed surface per grain to the solvent, here is how. Imagine the powdered substance bunched up together to make the small pellet, grains at the center of the pellet is blocked by other grains around it, and will take time before it comes in contact with the solvent. For the powdered grains, each grain has a surface independently exposed to the solvent and can easily come in contact with the solvent, taking less time to react with the solvent.

Technically, a powdered substance has more exposed surface area and logically will take a shorter time for the reaction to be complete.

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3690 J of heat are added to a 21.5 g sample
Fiesta28 [93]

Answer:

693K

Explanation:

The enthalpy change in the iron is 3690J

We now apply the formula for enthalpy change which is ΔH=mC∅ where ∅ is the temperature change, m the mass of the substance, and C the specific heat capacity for the substance.

ΔH in this case is 3690J.

Therefore 3690J=21.5g×0.449J/g.K×∅

as we are looking for ∅, we make it the subject of the formula.

∅=3690J/(21.5g×0.44J/g)

∅=390

Temperature=30°C +390

=420°+273

=693K

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3 years ago
Which of the following is not a chemical property?
malfutka [58]
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3 years ago
If 30 grams of KCl is dissolved at 10°C, how many additional grams would be needed to make the solution saturated at 60°C? * Cap
MariettaO [177]

If 30 grams of KCl is dissolved at 10°C, 14 g of KCl should be added to make a saturated solution at 60 °C.

<h3>What is a saturated solution?</h3>

A saturated solution is a solution in which there is so much solute that if there was any more, it would not dissolve. Its concentration is the same as the solubility at that temperature.

  • Step 1. Calculate the mass of water.

At 10 °C, the solubility is 31.2 g KCl/100 g H₂O.

30 g KCl × 100 g H₂O/31.2 g KCl = 96 g H₂O

  • Step 2. Calculate the mass of KCl required to prepare a saturated solution at 60 °C.

At 60 °C, the solubility is 45.8 g KCl/100 g H₂O.

96 g H₂O × 45.8 g KCl/100 g H₂O = 44 g KCl

  • Step 3. Calculate the mass of KCl that must be added.

44 g - 30 g = 14 g

If 30 grams of KCl is dissolved at 10°C, 14 g of KCl should be added to make a saturated solution at 60 °C.

Learn more about saturated solutions here: brainly.com/question/24564260

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Answer:1 mL

Explanation:

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