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Otrada [13]
3 years ago
5

Absalon adds 1 g of salt to 1 L of room temperature water (25 °C). Then, he starts a timer and observes what happens. He notices

that it takes 1 minute for the salt to dissolve. He decides to repeat his experiment, and he adds 1 g of salt to another 1 L of room temperature water (25 °C). After he adds the salt, he starts a timer. But, instead of watching the salt dissolve, he stirs the salt and water with a spoon until it dissolves. He notices that it only takes 30 seconds for the salt to dissolve in his second experiment.
Why does the salt dissolve faster in Absalon's second experiment?


Stirring the salt and water increases the polarity of the water molecules, which causes the ionic bonds of the salt to break.

Stirring the salt and water increases particle motion, which causes more collisions to occur between the water and salt.

Stirring the salt and water increases the surface area of the water, which causes more collisions to occur between the water and salt.

Stirring the salt and water increases the pressure on the solution, which causes the ionic bonds of the salt to break.
Chemistry
2 answers:
igor_vitrenko [27]3 years ago
7 0

Answer: Option (b) is the correct answer.

Explanation:

When Absalon stirred the solution which is containing salt in water then there will occur disturbance into solution due to stirring.

As a result, particles will come in motion and hence, they tend to gain more kinetic energy. Due to which there will be more number of collisions between the solute (salt) and solvent (water) particles.

Hence, rate of reaction will increase and because of this salt will readily dissolve into water.

Thus, we can conclude that the salt dissolve faster in Absalon's second experiment because stirring the salt and water increases particle motion, which causes more collisions to occur between the water and salt.

lana [24]3 years ago
6 0

Answer:

B

Explanation:

I looked it up and found the answer lol

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Which is the strongest acid listed in the table?
andrew11 [14]

Answer:

Hydrofluoric acid.

Explanation:

To know which of the acid is the strongest, let us determine the pka of each acid. This is illustrated below:

1. Acetic acid

Ka = 1.8x10^-5

pKa =..?

pKa = –logKa

pKa = –Log 1.8x10^-5

pKa = 4.74

2. Benzoic acid

Ka = 6.5x10^-5

pKa =..?

pKa = –logKa

pKa = –Log 6.5x10^-5

pKa = 4.18

3. Hydrofluoric acid.

Ka = 6.8x10^-4

pKa =..?

pKa = –logKa

pKa = –Log 6.8x10^-4

pKa = 3.17

4. Hypochlorous acid

Ka = 3.0x10^-8

pKa =..?

pKa = –logKa

pKa = –Log 3.0x10^-8

pKa = 7.52

Note: the smaller the pKa value, the stronger the acid.

The pka of the various acids as calculated above is given below:

Acid >>>>>>>>>>>>>>>>>> pKa

1. Acetic acid >>>>>>>>>> 4.74

2. Benzoic acid >>>>>>>> 4.18

3. Hydrofluoric acid >>>> 3.17

4. Hypochlorous acid >> 7.52

From the above illustration, we can see that hydrofluoric acid has the lowest pKa value. Therefore, hydrofluoric acid is the strongest among them.

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