<em>D</em> = 0.9570 g/mL
Mass of mixture = 88.219 g – 40.368 g = 47.851 g
<em>D</em> = mass/volume = 47.851 g/50.00 mL = 0.9570 g/mL
Answer:
Option c.
Explanation:
According to Newton's law, formula to solve this problem is:
F = m . a
Mass → 1000 kg
a → 3 m/s²
F = 1000 kg . 3m/s² → 3000 N
1 N = 1 kg . m/s² according to SI, Internation System of units.
Answer:
Its final temperature is 25.8 °C
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
There is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:
Q = c * m * ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation (ΔT=Tfinal-Tinitial)
When a body transmits heat there is another that receives it. This is the principle of the calorimeter. Then the heat released by the compound will be equal to the heat obtained by the calorimeter.
In this case, you know:
- c= 3.55
![\frac{J}{g*C}](https://tex.z-dn.net/?f=%5Cfrac%7BJ%7D%7Bg%2AC%7D)
- m=1.20 kg= 1200 g (1 kg=1000 g)
- Tfinal= ?
- Tinitial= 22.5 °C
Replacing:
![14,000 J= 3.55 \frac{J}{g*C}*1200 g*(Tfinal-22.5C)](https://tex.z-dn.net/?f=14%2C000%20J%3D%203.55%20%5Cfrac%7BJ%7D%7Bg%2AC%7D%2A1200%20g%2A%28Tfinal-22.5C%29)
Solving:
![\frac{14,000J}{3.55\frac{J}{g*C} *1200 g} =T final - 22.5C](https://tex.z-dn.net/?f=%5Cfrac%7B14%2C000J%7D%7B3.55%5Cfrac%7BJ%7D%7Bg%2AC%7D%20%2A1200%20g%7D%20%3DT%20final%20-%2022.5C)
3.3=Tfinal - 22.5 C
3.3 + 22.5=Tfinal
Tfinal= 25.8 °C
<u><em>Its final temperature is 25.8 °C</em></u>
Acquired, because everyone has to learn how to speak English you can’t just be born and know how to speak.
There are 4 quantum numbers that can be used to describe the space of highest probability an electron resides in.
First quantum number is the principal quantum number- n , states the energy level.
Second quantum number states the angular momentum quantum number - l,
states the subshell and the shape of the orbital
values of l for n energy shells are from 0 to n-1
third is magnetic quantum number - m, which tells the specific orbital.
fourth is spin quantum number - s - gives the spin of the electron in the orbital
here we are asked to find l for 3p1
n = 3
and values of l are 0,1 and 2
for p orbitals , l = 1
therefore second orbital for 3p¹ is 1.