<u>Answer:</u> Aluminium is getting oxidized in the given chemical reaction.
<u>Explanation:</u>
Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.
Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.
For the given chemical reaction:
The half cell reactions for the above reaction follows:
<u>Oxidation half reaction:</u> 
<u>Reduction half reaction:</u> 
As, aluminium is loosing 3 electrons to form aluminium cation. Thus, it is getting oxidized. Iron is gaining 2 electrons to form iron anion. Thus, it is getting reduced.
Hence, the oxidized species of the given reaction is aluminium.
Answer:
357 g of the transition metal are present in 630 grams of the compound of the transition metal and iodine
Explanation:
In any sample of the compound, the percentage by mass of the transition metal is 56.7%. This means that for a 100 g sample of the compound, 56.7 g is the metal while the remaining mass, 43.3 g is iodine.
Given mass of sample compound = 630 g
Calculating the mass of iodine present involves multiplying the percentage by mass composition of the metal by the mass of the given sample;
56.7 % = 56.7/100 = 0.567
Mass of transition metal = 0.567 * 630 = 357.21 g
Therefore, the mass of the transition metal present in 630 g of the compound is approximately 357 g
Answer:
1 I'm doing this in science class right now I got help yesturday on it! hope this helps
Explanation:
during this reaction this will produce 2 molecules of No
Answer:
<h3>I think, berryllium oxide, is answer. </h3>
Explanation:
<h3>Hope it helps you....</h3>
