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Svet_ta [14]
3 years ago
9

Arachidonic acid and pge1 are both carboxylic acids with atoms. the differences are that arachidonic acid contains and no other

functional groups, whereas pge1 has . in addition, a part of the pge1 chain forms
a.

Chemistry
1 answer:
hichkok12 [17]3 years ago
8 0
Answer:
             <span>Arachidonic Acid and PGE</span>₁<span> are both carboxylic acids with <u>Twenty Carbon</u> atoms. The differences are that Arachidonic acid contains <u>Four <em>cis</em> Double Bonds</u> and no other functional groups, whereas PGE</span>₁<span> has <u>One <em>Trans</em> Double Bond, Two Hydroxyl and One Ketone Functional Groups.</u>. In addition, a part of the PGE</span>₁<span> chain forms a <u>Five Membered Ring</u>.

Structures of Both Arachidonic Acid and PGE</span>₁ are shown Below,

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The unit pg stands for pictogram. It is one-trillionth of a gram. Because of the very small mass, it is expressed in the prefix form of the base units for convenience. Now, the mass of cofactor a is 41.5 pg per cell. Since there are a total of 105 cells, the total mass would be:

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How did Wegener use similar mountain ranges and areas made of certain types of rock found in Africa and South American as eviden
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the Germany scientist Alfred Wagner describes fold mountains that are found in The world are the same also geological similarity that occur between this continent are the same for example the rock that are found in brazil are the same of that of south africa.

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Cuales elementos tienen solo un electrón de valencia ​
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5 0
2 years ago
How many milliliters of 4.00 M NaOH are required to exactly neutralize 50.0 milliliters of a 2.00 M solution of HNO3 ?
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Answer: The volume of NaOH required is 25.0 ml

Explanation:

According to the neutralization law,

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity HNO_3 = 1

M_1 = molarity of HNO_3 solution = 2.00 M

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n_2 = acidity of NaOH = 1

M_1 = molarity of NaOH solution = 4.00 M

V_1 = volume of  NaOH solution =  ?

Putting in the values we get:

1\times 2.00\times 50.0=1\times 4.00\times V_2

V_2=25.0ml

Therefore, volume of NaOH required is 25.0 ml

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3 years ago
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