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jeka57 [31]
3 years ago
12

A student sets up the following equation to convert a measurement. (The stands for a number the student is going to calculate.)

Fill in the missing part of this equation. Note: your answer should be in the form of one or more fractions multiplied together.

Chemistry
1 answer:
Crank3 years ago
3 0

Answer:

0.090 J/(mmol·°C) × (1000 mmol/mole × 1 kJ/(1000 J)) = 0.090 kJ/mole

Explanation:

The unit of conversion from kilo-Joules to Joules is given as follows;

1000 Joules = 1 kilo-Joule

The unit of conversion from milimoles to moles is given as follows;

1000 milimoles = 1 Mole

Therefore, we have

The value of the given expression is 0.090 J/(mmol·°C) × 1000 mmol/mole × 1 kJ/(1000 J) = 0.090 kJ/mole

0.090 J/milimole = 0.09 kJ/mole.

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A 170.0 g sample of an unidentified compound contains 29.84 g sodium, 67.49
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The empirical formula : Na₂Cr₂O₇

<h3>Further explanation</h3>

Given

170 g sample contains :

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Required

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Solution

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Na : 29.84 : 23 g/mol = 1.297

Cr : 67.49 : 51,9961 g/mol = 1.297

O : 72.67 : 16 g/mol = 4.54

Divide by 1.297

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The molar mass of...

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adelina 88 [10]

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6. Consider the reaction: CzHo (g) + 02 (8) - 4 CO2(g) + 6H2O (1)
deff fn [24]

Answer:

1120 gm

Explanation:

6. Consider the reaction: CzHo (g) + 02 (8) - 4 CO2(g) + 6H2O (1)

(a) Balance the equation.

(b) How many grams of oxygen are required to react with 10 moles of ethane for a complete

combustion reaction?

FIRST, CORRECT THE EQUATION THEN BALANCE

2C2H6(G) + 7O2------------>  4CO2  + 6H2O

so for 10 moles of ethane, we need

7 X 5 = 35 MOLES O2

=35 MOLES O2

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