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Gre4nikov [31]
3 years ago
9

An element with the smallest anionic (negative-ionic) radius would be found on the periodic table in

Chemistry
1 answer:
Advocard [28]3 years ago
5 0
The correct answer for, An element with the smallest anionic (negative-ionic) radius would be found on the periodic table in, is <span>Group 17, Period 2.</span>
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using the following thermochemical equation, determine the amount of heat produced from the combustion of 24.3 g benzene (c6h6).
aliya0001 [1]

the amount of heat produced from the combustion of 24.3 g benzene (c6h6) is ΔH = -976.5 kJ

There are two moles of benzene involved in the process (C6H6). Since the heat of this reaction is -6278 kJ, the burning of 2 moles of benzene will result in a heat loss of 6278 kJ. This reaction is exothermic.

Enthalpy, or the value of H, is a unit of measurement for heat that relies on the amount of matter present (number of moles).

Thus, 24.3 g of benzene contains:

n = mass/molar mass, where n = 24.3/78.11, and n = 0.311 moles.

2 moles = 6278 kJ

0.311 moles =x

By the straightforward direct three rule:

2x = -1953.08 x = -976.5 kJ

Learn more about combustion here-

brainly.com/question/15117038

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4 0
1 year ago
1. write the formula for the following ionic compound: Calcium Carbonate
Salsk061 [2.6K]

Answer:

CaCO3

Explanation:

The molecule is formed by the calcium cation Ca+2 and the carbonate anion CO3−2.

3 0
2 years ago
Definition of instantaneous speed
Sindrei [870]

Answer:

Explanation:

The instantaneous speed is the speed of an object at a particular moment in time. And if you include the direction with that speed, you get the instantaneous velocity.

3 0
3 years ago
Given that a mass of a ball is (36.0 g), and the volume is (8.0 mL), what is the ball's density in g/mL?​
max2010maxim [7]

Answer:

4.5g/mL

Explanation:

Given parameters:

Mass of ball  = 36g

Volume of the ball  = 8mL

Unknown:

Density of the ball  = ?

Solution:

Density is the mass per unit volume of a substance.

          Density  = \frac{mass}{volume}  

So;

 Density  = \frac{36}{8}    = 4.5g/mL

5 0
3 years ago
How many joules are needed to change the temperate of 22g of water from 18°C to 33°C?
Ira Lisetskai [31]

Answer:

Q =  1379.4 J

Explanation:

Given data:

Mass of water = 22  g

Initial temperature = 18°C

Final temperature = 33°C

Heat absorbed = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Specific heat capacity of water is 4.18 J/g. °C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 33°C - 18 °C

ΔT =  15°C

Q = 522 g ×4.18 J/g.°C× 15°C

Q =  1379.4 J

5 0
3 years ago
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