<span>(a)

Taking the angle of the pitch, 37.5°, and the particle's initial velocity, 18.0 ms^-1, we get:

18.0*cos37.5 = v_x = 14.28 ms^-1, the projectile's horizontal component.

(b)
To much the same end do we derive the vertical component:

18.0*sin37.5 = v_y = 10.96 ms^-1

Which we then divide by acceleration, a_y, to derive the time till maximal displacement,

10.96/9.8 = 1.12 s

Finally, doubling this value should yield the particle's total time with r_y > 0

<span>2.24 s

I hope my answer has come to your help. Thank you for posting your question here in Brainly.
</span></span>

6 0

3 years ago

A long electric cable is suspended above the earth and carries a current of 345 A parallel to the surface of the earth. The eart

jok3333 [9.3K]

Answer:

0.906 N

Explanation:

Formula for magnetic force acting on current carrying cable:

$F = IBLsin(\theta)$

Where I = 345A is the current in the wire, B = $5.6*10^{-5} T$ is the magnetic magnitude generated by Earth. L = 46.9 m is the cable length. $\theta = 88.2^o$ is the angle between vector B and cable direction.