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Mademuasel [1]
2 years ago
7

The activation energy for a(n) _____ is quite large and usually takes extra energy from the environment, it is normally not a na

tural spontaneous process. combustion reaction endothermic reaction exothermic reaction catalyzed reaction
Chemistry
2 answers:
aev [14]2 years ago
5 0

Answer:

endothermic reaction

Explanation:

The activation energy of an endothermic reaction is high. Endothermic reactions need heat to start and do not begin spontaneously. Activation energy is the minimum energy required to convert reactants to products.  The lower the activation energy the easier it is too start a reaction and vice versa. Catalyst helps to lower the activation energy and thereby speed up a chemical reaction.

Ira Lisetskai [31]2 years ago
3 0

Answer:

The activation energy for an endothermic reaction is quite large and usually takes extra energy from the environment, it is normally not a natural spontaneous process.

Explanation:

  • Endothermic reactions require absorbing energy of the surrounding mainly in the form of heat.
  • Chemical energy needs energy input to break the bonds.
  • Examples of endothermic reactions: Photosynthesis , melting of ice , and evaporating liquid water.
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How many milliliters of water will it take to fill a 2 L bottle that already contains 1.87 L of water?
Aloiza [94]

Answer:

0.00013

Explanation:

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2 years ago
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Explanation:

4 0
2 years ago
An industrial chemist studying bleaching and sterilizing prepares several hypochlorite buffers. Find the pH of 0.200 M HClO and
stellarik [79]

Answer:

The pH is 7.54

Explanation:

The Henderson - Hasselbalch equation states that for a buffer solution which consists of a weak acid and its conjugate base, the buffer pH is given by:

pH =pk_{a} +log(\frac{[conjugate base]}{[weakacid]})

pkₐ is for the acid

In this case, the buffer hypochlorous acid  HClO is a weak acid, and its conjugate base is the hypochlorite anion ClO⁻  is delivered to the solution via sodium hypochlorite NaClO .

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HCIO = 0.200 M

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∴pH = =7.54 +log\frac{0.2}{0.2} = 7.54

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