Answer:
1.008moles of iodine
Explanation:
Hello,
This question requires us to calculate the theoretical yield of I₂ or number of moles that reacted.
Percent yield = (actual yield / estimated yield) × 100
Actual yield = 1.2moles
Estimated yield = ?
Percentage yield = 84%
84 / 100 = 1.2 / x
Cross multiply and solve for x
100x = 84 × 1.2
100x = 100.8
x = 100.8/100
x = 1.008moles
1.008 moles of I₂ reacted in excess of H₂ to give 1.2 moles of HI
Answer:
hold on this will take me awhile
Explanation:
Assuming you are asking for the names of the elements in that formula , the answer is
carbon
hydrogen
chlorine
fluorine
sodium
oxygen
Answer:
4. Principal and Azimuthal (subsidiary) quantum number
5.Principal, Azimuthal (subsidiary), and magnetic quantum number
6. 10 electrons
7. 32 electrons
8. 36 electrons
Explanation:
4. Principal and Azimuthal (subsidiary) quantum number because in 4d, 4 represent principal quantum number and d- represents azimuthal quantum number (having l- value as 3)
5.Principal, Azimuthal (subsidiary), and magnetic quantum number are the first three because 2 stands for principal, s-for azimuthal (l=0) and magnetic quantum number for s- orbital= 0
6. 10 electrons, because for sublevel with l= 3, is a d-sub-level, and d- can take 10-electrons
7. 32 electrons, using the relationship 2×n^2 for the maximum number of electrons in a shell,
,n= 4 , hence 2×4^2= 32
8. 36 electrons, because n=4 and n= 3 can have the maximum configuration of [Ar]4s^2 3d^10 4p^6
This will sum up to 36- electrons, since Argon has 18 -electrons.
18+2+10+6=36 electrons
