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Fiesta28 [93]
2 years ago
5

HELP ME PLZ

Chemistry
1 answer:
Alex73 [517]2 years ago
8 0
The answer should be The Tyndall Effect
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historically, the medical consequence suffered by consumers exposed to lead is A.) Stunted growth B.) infection C.) rashes D.) b
Oxana [17]

Lead can cause

D.) brain damage

Explanation:

Lead poisoning is a sort of metal poisoning generated by lead in the body. The brain is the most sensitive. Symptoms may comprise abdominal pain, illness, headaches, irritability, thought problems, inability to have children, and tingling in the hands and feet. It causes almost 10% of the intelligent weakness of otherwise unknown cause also can result in behavioral problems. Some of the outcomes are strong. In severe cases, anemia, convulsions, coma, or death may occur.

4 0
3 years ago
Read 2 more answers
If a sample of gas is at 672 °C and 3.9 atm, what is the new temperature at 12.2 atm?
Snowcat [4.5K]
In order to calculate the final temperature of the gas, we may apply Charles's law, which states that the pressure and temperature of a fixed amount of gas at constant volume are directly proportional. Mathematically:
P/T = constant
(absolute temperature is used, so T = 672 + 273 = 945 K)
Thus,
3.9 / 945 = 12.2 / T
T = 2,956 K or 2,683 °C
7 0
3 years ago
I NEED HELP ASAP PLZ LOOK AT THE PICTURE CAREFULLY!!!!
Virty [35]

Answer:

it is a little fuzzy

Explanation:

6 0
2 years ago
Determine the electrical work required to produce one mole of hydrogen in the electrolysis of liquid water at 298°K and 1 atm. T
Ostrovityanka [42]

Explanation:

The given data is as follows.

          \Delta H = 286 kJ = 286 kJ \times \frac{1000 J}{1 kJ}

                            = 286000 J

 S_{H_{2}O} = 70 J/^{o}K,      S_{H_{2}} = 131 J/^{o}K

 S_{O_{2}} = 205 J/^{o}K

Hence, formula to calculate entropy change of the reaction is as follows.

          \Delta S_{rxn} = \sum \nu_{i}S_{i}_(products) - \sum \nu_{i}S_{i}_(reactants)

                     = [(\frac{1}{2} \times S_{O_{2}}) - (1 \times S_{H_{2}})] - [1 \times S_{H_{2}O}]

                    = [(\frac{1}{2} \times 205) + (1 \times 131)] - [(1 \times 70)]

                    = 163.5 J/K

Therefore, formula to calculate electric work energy required is as follows.

             \Delta G_{rxn} = \Delta H_{rxn} - T \Delta S_{rxn}

                            = 286000 J - (163.5 J/K \times 298 K)

                            = 237.277 kJ

Thus, we can conclude that the electrical work required for given situation is 237.277 kJ.

6 0
3 years ago
A truck is moving at the rate of 40 km/hr. How far does it move when it stops after 5 seconds?
seraphim [82]
First of all, this is the chemistry section, while your question is a physics question. Anyway I'll tell you how to solve it.

First we need to find the rate that the truck moves in a second.

1km = 1000m
40km = 40000m
40000m/hr
1 hour = 60 minutes
40000m/hr ÷ 60 = 666.66(repeating)/minute
1 minute = 60 seconds
666.66m/min ÷ 60 = 11.11(rep)m/s

Next we simply multiply the speed of the truck by the number of seconds it travels.

11.11 × 5 = 55.55
Make sure to round it unless you indicate the repeating decimal.
The truck moved 55.56m in 5 seconds.
6 0
3 years ago
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