Answer:
Problem 1:
a. x=2
b. x=3
c. x=1
Problem 2:
A multiplication equation to hold the table true:

A division equation to hold the table true:

Step-by-step explanation:
Given in problem 1:
(a). The equation is 
It holds true for all values of
.
Let us say
,
which is greater than 1.
(b). The equation is 
It holds true for all values of
.
Let us say 
which is less than 1.
(c). The equation is 
It holds true for only
.
Let us say
,
which is equal to 1.
Problem 2:
A multiplication equation to hold the table true:

A division equation to hold the table true:

Therefore these are the values which hold true to the equation in problem 1 and 2.
Answer:
f(g(x))=16x^2+6x-4
Step-by-step explanation:
f(g(x))=4(2x)^2 +3(2x)-4
f(g(x))=16x^2+6x-4
I think the question is wrong!
It must be
x-4
___= 5
x+2
Answer: x - 4= 5x + 10
or,-10 -4 = 5x - x
or, -14=4x
or,-14/4= x
Therefore, x = -14/4
This is the diference of 2 perfect squares. 4 is a perfect square, x^2 is a perfect square, and 25 is a perfect square. The pattern for this is (ax + b)(ax - b). Our a is 2 since 2*2 = 4, and our b is 5 since 5*5 = 25. So your factors are (2a+5)(2a-5), choice C.