All categories

3 years ago

-6x+3x^2+10x^2 simplified

Mathematics

1 answer:

Rus_ich [418]3 years ago

3 0

$-6x+3x^2+10x^2=(3x^2+10x^2)-6x=13x^2-6x$

You might be interested in

Which of the following is the product of the rational expression shown below

wolverine [178]

Option C: $\frac{x^{2}-9}{x^{2}-4}$ is the product of the rational expression.

Explanation:

The given rational expression is $\frac{x+3}{x+2} \cdot \frac{x-3}{x-2}$

We need to determine the product of the rational expression.

<u>Product of the rational expression:</u>

Let us multiply the rational expression to determine the product of the rational expression.

Thus, we have;

$\frac{(x+3)(x-3)}{(x+2)(x-2)}$

Let us use the identity $(a+b)(a-b)=a^2-b^2$ in the above expression.

Thus, we get;

$\frac{x^{2} -3^2}{x^{2} -2^2}$

Simplifying the terms, we get;

$\frac{x^{2}-9}{x^{2}-4}$

Thus, the product of the rational expression is $\frac{x^{2}-9}{x^{2}-4}$

Hence, Option C is the correct answer.

6 0

3 years ago

Matt decides the length of his table will be 15 in. He calculates that the area of the table is 30 in. squared. Determine if Mat

Allushta [10]

Answer:No Matt's calculation is not correct.

Step-by-step explanation:

We have to multiply by the number of the area.If it is 4 inches we multiply by 4

15 x 4 =60

A=4 inches squared

A=LxW (length x width )

so you can say that:

Matt is incorrect because He skipped the step of multiplying 2 by 2 in the formula which is where we get 4 from.

8 0

2 years ago

Classify the polynomial.<br><br> 3r^5-2r^2+5r

ella [17]

Answer: 5th degree trinomial

The degree is 5 because its the largest exponent of the single variable polynomial.

It's a trinomial because there are 3 terms. The terms are separated by a plus or a minus.

7 0

3 years ago

In the figure below, segment CD is parallel to segment EF and point H bisects segment DE :

Grace [21]

Answer:

See explanation

Step-by-step explanation:

In the figure below, segment CD is parallel to segment EF, DE is a transversal, then angles DIH and HGI are congruent as alternate interior angles when two parallel lines are cut by a transversal.

Consider triangles DIH and EGH. In these triangles,