Take Sally's position to be the origin, and up-the-ramp to be the positive direction. The ball travels a distance <em>x</em> in time <em>t</em> of
<em>x</em> = <em>u</em> <em>t</em> + 1/2 (- 3.7 m/s²) <em>t</em>²
where <em>u</em> is the ball's initial velocity.
Its velocity <em>v</em> at time <em>t</em> is
<em>v</em> = <em>u</em> + (- 3.7 m/s²) <em>t</em>
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Let <em>T</em> be the time it takes for the ball to reach the second person 19.6 m up the ramp. At this time, the ball attains a velocity of 4.9 m/s, so that
4.9 m/s = <em>u</em> + (- 3.7 m/s²) <em>T</em>
<em>T</em> = (<em>u</em> - 4.9 m/s) / (3.7 m/s²)
Substitute this into the distance equation, with <em>x</em> = 19.6 m, and solve for <em>u</em> :
19.6 m = <em>u</em> (<em>u</em> - 4.9 m/s) / (3.7 m/s²) + 1/2 (- 3.7 m/s²) ((<em>u</em> - 4.9 m/s) / (3.7 m/s²))²
<em>u</em> ≈ 13 m/s
The correct answer is; Yes, you can be unconsciously eavesdropping.
Further Explanation:
When this occurs it is called the “The Cocktail Party Phenomenon.” Your mind can focus on one conversation that is being made and drown out all other speech and things going on around you. This makes your brain have auditory attention on one specific conversation.
The sensory hearing in the person listening to the conversation is subconsciously filtering the conversation into its own stream in the brain. This phenomenon can also detect certain words that are important to the person with a large amount of noise in the background.
This occurs in the left hemisphere of the brain in the superior temporal gyrus region.
Learn more about the Cocktail Party Phenomenon at brainly.com/question/14532863
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Answer:
1. 12 V
2a. R₁ = 4 Ω
2b. V₁ = 4 V
3a. A = 1.5 A
3b. R₂ = 4 Ω
4. Diagram is not complete
Explanation:
1. Determination of V
Current (I) = 2 A
Resistor (R) = 6 Ω
Voltage (V) =?
V = IR
V = 2 × 6
V = 12 V
2. We'll begin by calculating the equivalent resistance. This can be obtained as follow:
Voltage (V) = 12 V
Current (I) = 1 A
Equivalent resistance (R) =?
V = IR
12 = 1 × R
R = 12 Ω
a. Determination of R₁
Equivalent resistance (R) = 12 Ω
Resistor 2 (R₂) = 8 Ω
Resistor 1 (R₁) =?
R = R₁ + R₂ (series arrangement)
12 = R₁ + 8
Collect like terms
12 – 8 =
4 = R₁
R₁ = 4 Ω
b. Determination of V₁
Current (I) = 1 A
Resistor 1 (R₁) = 4 Ω
Voltage 1 (V₁) =?
V₁ = IR₁
V₁ = 1 × 4
V₁ = 4 V
3a. Determination of the current.
Since the connections are in series arrangement, the same current will flow through each resistor. Thus, the ammeter reading can be obtained as follow:
Resistor 1 (R₁) = 4 Ω
Voltage 1 (V₁) = 6 V
Current (I) =?
V₁ = IR₁
6 = 4 × I
Divide both side by 4
I = 6 / 4
I = 1.5 A
Thus, the ammeter (A) reading is 1.5 A
b. Determination of R₂
We'll begin by calculating the voltage cross R₂. This can be obtained as follow:
Total voltage (V) = 12 V
Voltage 1 (V₁) = 6 V
Voltage 2 (V₂) =?
V = V₁ + V₂ (series arrangement)
12 = 6 + V₂
Collect like terms
12 – 6 = V₂
6 = V₂
V₂ = 6 V
Finally, we shall determine R₂. This can be obtained as follow:
Voltage 2 (V₂) = 6 V
Current (I) = 1.5 A
Resistor 2 (R₂) =?
V₂ = IR₂
6 = 1.5 × R₂
Divide both side by 1.5
R₂ = 6 / 1.5
R₂ = 4 Ω
4. The diagram is not complete
<em>HERE'S</em><em> </em><em>YOUR</em><em> </em><em>ANSWER</em><em>: </em>
•Since the log is stationary and you are moving beside the log, it seems to move in the opposite direction from your point of view, because from your perspective u are stationary and the log is moving. If you were to stop moving the log would also stop moving.
<em>HOPE</em><em> </em><em>IT</em><em> </em><em>HELPS</em><em>.</em><em>.</em><em>.</em>