Answer:
0.1 s
Explanation:
The net force on the log is F - f = ma where F = force due to winch = 2850 N, f = kinetic frictional force = μmg where μ = coefficient of kinetic friction between log and ground = 0.45, m = mass of log = 300 kg and g = acceleration due to gravity = 9.8 m/s² and a = acceleration of log
So F - f = ma
F - μmg = ma
F/m - μg = a
So, substituting the values of the variables into the equation, we have
a = F/m - μg
a = 2850 N/300 kg - 0.45 × 9.8 m/s²
a = 9.5 m/s² - 4.41 m/s²
a = 5.09 m/s²
Since acceleration, a = (v - u)/t where u = initial velocity of log = 0 m/s (since it was a rest before being pulled out of the ditch), v = final velocity of log = 0.5 m/s and t = time taken for the log to reach a speed of 0.5 m/s.
So, making t subject of the formula, we have
t = (v - u)/a
substituting the values of the variables into the equation, we have
t = (v - u)/a
t = (0.5 m/s - 0 m/s)/5.09 m/s²
t = 0.5 m/s ÷ 5.09 m/s²
t = 0.098 s
t ≅ 0.1 s
Answer:
Here are some uses...
Explanation:
Uses of convex mirror:
It is used in supermarkets and stores for surveillance.
It it is used as rear view mirror in automobiles.this is due to the reason that a convex mirror provides a wider field of view than a plane or concave mirror.
Uses of concave mirror:
It is used in torches.
They are used in headlights of vehicles to send parallel rays to infinity , in shaving mirror to get an enlarged image of the face and also by dentists to see a bigger image of the tooth / teeth .
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Answer:
Time period, T = 1.98 seconds
Explanation:
It is given that,
Mass of the block, m = 300 g = 0.3 kg
Force constant of the spring, k = 3 N/m
Displacement in the block, x = 3 cm
Let T is the period of the motion of the block. The time period of the block is given by :
T = 1.98 seconds
So, the period of the motion of the block is 1.98 seconds. Hence, this is the required solution.
Answer:
The amplitude after 75 s, x(t) = 0.558 m
Given:
Initial Amplitude, A = 1.8 m
time constant, 
= 32 s
Solution:
Now, to calculate the amplitude of the damped oscillation after 75 s, we use the relation:
Amplitude after 75 s, x(t) = A
Now, putting the value in the above relation:
x(t) = 1.8
x(t) = 1.8
x(t) = 0.558 m
