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serg [7]
3 years ago
13

This is a written question.

Physics
1 answer:
navik [9.2K]3 years ago
8 0

Answer:

2

Explanation:

it freezes from liquid to solids

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What is the equivalent resistance for a parallel circuit that has two resistors: 18.0 ohms and 23.5 ohms?
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With only two resistors in parallel, it's relatively easy
to calculate their combined equivalent resistance.

                       R  =  (their product) / (their sum)

                           =  (18Ω x 23.5Ω) / (18Ω + 23.5Ω)

                           =           (423Ω²)  /  (41.5Ω)

                           =    10.2 Ω
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3 years ago
In an RLC series circuit that includes a source of alternating current operating at fixed frequency and voltage, the resistance
maw [93]

Answer:

Capacitive Reactance is 4 times of resistance

Solution:

As per the question:

R = X_{L} = j\omega L = 2\pi fL

where

R = resistance

X_{L} = Inductive Reactance

f = fixed frequency

Now,

For a parallel plate capacitor, capacitance, C:

C = \frac{\epsilon_{o}A}{x}

where

x = separation between the parallel plates

Thus

C ∝ \frac{1}{x}

Now, if the distance reduces to one-third:

Capacitance becomes 3 times of the initial capacitace, i.e., x' = 3x, then C' = 3C and hence Current, I becomes 3I.

Also,

Z = \sqrt{R^{2} + (X_{L} - X_{C})^{2}}

Also,

Z ∝ I

Therefore,

\frac{Z}{I} = \frac{Z'}{I'}

\frac{\sqrt{R^{2} + (R - X_{C})^{2}}}{3I} = \frac{\sqrt{R^{2} + (R - \frac{X_{C}}{3})^{2}}}{I}

{R^{2} + (R - X_{C})^{2}} = 9({R^{2} + (R - \frac{X_{C}}{3})^{2}})

{R^{2} + R^{2} + X_{C}^{2} - 2RX_{C} = 9({R^{2} + R^{2} + \frac{X_{C}^{2}}{9} - 2RX_{C})

Solving the above eqn:

X_{C} = 4R

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An Apple falls from a tree and one-half second later hits the ground
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