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bagirrra123 [75]
3 years ago
6

5 everyday chemical reactions

Chemistry
2 answers:
KatRina [158]3 years ago
3 0
1) Photosynthesis
2) Rust
3) Mixing Chemicles (like salt and vinegar)
4) Digestion
5) Soaps and detergents. (washing clothes)

~Hope this helped

Ket [755]3 years ago
3 0
Stirring
Food digesting inside of you
Boiling water
Freezing water
Fire
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Which is a polar molecule?
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A polar molecule is when the arrangement of the atoms in molecules are unequal where one end of the molecule has a positive charge while the other end has a negative charge. Examples of a polar molecule are water, ammonia, hydrogen sulfide and sulfur dioxide. The opposite is called a nonpolar molecule. 
5 0
3 years ago
17)<br> How many grams are in 0.02 moles of beryllium iodide, Bel2?
Alinara [238K]

Answer:

beryllium iodide has a molar mass of 262.821 g mol−1 , which means that 1 mole of beryllium iodide has a mass of 262.821 g . To find the mass of 0.02 moles of beryllium iodide, simply multiply the number of moles by the molar mass in conversion factor form.

Explanation:

5 0
3 years ago
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Consider the formation of hcn by the reaction of nacn (sodium cyanide) with an acid such as h2so4 (sulfuric acid): 2nacn(s)+h2so
Artemon [7]

2NaCN(s) + H₂SO₄(aq) --> Na₂SO₄(aq) + 2HCN(g)  

The molar ratio between NaCN : HCN is 2:2  or 1:1

Mass of HCN = 16.7 g

Molar mass of HCN = 1 + 12 + 14 = 27 g/mol

Molar mass of NaCN = 49 g/mol

Therefore, the mass of NaCN is

16.7 g of  HCN x 49 g/mol of NaCN / 27 g/mol of HCN = 30.3 grams of NaCN

Therefore, 30.3 grams of NaCN gives the lethal dose in the room.

5 0
3 years ago
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If one pound is the same as 454 grams, then convert the mass of 78 grams to pounds.
LiRa [457]

Answer:

0.17 lb

Explanation:

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If you want additional help with chemistry or another subject for FREE, check out growthinyouth.org.

4 0
3 years ago
What is the value for AG at 5000 K if AH = -220 kJ/mol and S= -0.05 kJ/(mol-K)?
Serhud [2]

Answer:

C. 30 kJ

Explanation:

Hello there!

In this case, in agreement to the thermodynamic definition of the Gibbs free energy, in terms of enthalpy of entropy:

\Delta G= \Delta H-T\Delta S

It is possible to calculate the required G by plugging in the given entropy and enthalpy as shown below:

\Delta G=-220kJ/mol-5000K*-0.05kJ/mol*K\\\\\Delta G=30kJ/mol

Therefore, the answer is C. 30 kJ .

Best regards!

4 0
2 years ago
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