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dusya [7]
2 years ago
12

Which two types of reactions are also always redox reactions? Explain your answer.

Chemistry
2 answers:
Annette [7]2 years ago
8 0

Answer : The two types of reactions always redox reaction are, Single-displacement reaction and Disproportionation reaction.

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Single-displacement reaction : It is a type of reaction in which the most reactive element displaces the least reactive element from its compound.

It is type of redox reaction where a species simultaneously oxidized and reduced and form different products.

For example : Mg+CuSO_4\rightarrow MgSO_4+Cu

In this reaction, oxidation takes place when Mg lose electrons and form  Mg^{2+} and reduction takes place when Cu^{2+} gain electrons and form Cu.

Disproportionation reaction : It is a type of chemical reaction in which a molecule is converted or transformed into two or more different products.

It is type of redox reaction where a species simultaneously oxidized and reduced and form different products.

For example : 2H_2PO_4^-\rightarrow HPO_4^{2-}+H_3PO_4

In this reaction, oxidation and reduction reaction takes palace simultaneously by the one species that is, H_2PO_4^-.

In this reaction, oxidation takes place when H_2PO_4^- lose electrons and form HPO_4^{2-} and reduction takes place when H_2PO_4^- gain electrons and form H_3PO_4.

Hence, the two types of reactions always redox reaction are, Single-displacement reaction and Disproportionation reaction.

mina [271]2 years ago
7 0
Single displacement and combustion reactions are ALWAYS redox.
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Consider the following mechanism for the oxidation of bromide ions by hydrogen peroxide in aqueous acid solution. H+ + H2O2 ? H3
Margarita [4]

<u>Answer:</u> The rate law for the reaction is \text{Rate}=k'[H+][H_2O_2][Br^-]

<u>Explanation:</u>

Rate law is the expression which is used to express the rate of the reaction in terms of the molar concentration of reactants where each term is raised to the power their stoichiometric coefficient respectively from a balanced chemical equation.

In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.

The chemical equation for the oxidation of bromide ions by hydrogen peroxide in aqueous acid solution follows:

2H^++2Br^-+H_2O_2\rightarrow Br_2+2H_2O

The intermediate reaction of the mechanism follows:

<u>Step 1:</u>  H^++H_2O_2\rightleftharpoons H_3O_2^+;\text{ (fast)}

<u>Step 2:</u>  H_3O_2^++Br^-\rightarrow HOBr+H_2O;\text{(slow)}

<u>Step 3:</u>  HOBr+H^++Br^-\rightarrow Br_2+H_2O;\text{(fast)}

As, step 2 is the slow step. It is the rate determining step

Rate law for the reaction follows:

\text{Rate}=k[H_3O_2^+][Br^-]          ......(1)

As, [H_3O_2^+] is not appearing as a reactant in the overall reaction. So, we apply steady state approximation in it.

Applying steady state approximation for [H_3O_2^+] from step 1, we get:

K=\frac{[H_3O_2^+]}{[H^+][H_2O_2]}  

[H_3O_2^+]=K[H^+][H_2O_2]

Putting the value of [H_3O_2^+] in equation 1, we get:

\text{Rate}=k.K[H^+][H_2O_2][Br^-]\\\\\text{Rate}=k'[H+][H_2O_2][Br^-]

Hence, the rate law for the reaction is \text{Rate}=k'[H+][H_2O_2][Br^-]

4 0
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If an atom has 11 atomic number and 11 neutrons how many electrons are there??
Fantom [35]

Answer:

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Explanation:

The atomic number of sodium is 11. This tells us that sodium has 11 protons and because it is neutral it has 11 electrons. The mass number of an element tells us the number of protons AND neutrons in an atom (the two particles that have a measurable mass).

5 0
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