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dusya [7]
3 years ago
12

Which two types of reactions are also always redox reactions? Explain your answer.

Chemistry
2 answers:
Annette [7]3 years ago
8 0

Answer : The two types of reactions always redox reaction are, Single-displacement reaction and Disproportionation reaction.

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Single-displacement reaction : It is a type of reaction in which the most reactive element displaces the least reactive element from its compound.

It is type of redox reaction where a species simultaneously oxidized and reduced and form different products.

For example : Mg+CuSO_4\rightarrow MgSO_4+Cu

In this reaction, oxidation takes place when Mg lose electrons and form  Mg^{2+} and reduction takes place when Cu^{2+} gain electrons and form Cu.

Disproportionation reaction : It is a type of chemical reaction in which a molecule is converted or transformed into two or more different products.

It is type of redox reaction where a species simultaneously oxidized and reduced and form different products.

For example : 2H_2PO_4^-\rightarrow HPO_4^{2-}+H_3PO_4

In this reaction, oxidation and reduction reaction takes palace simultaneously by the one species that is, H_2PO_4^-.

In this reaction, oxidation takes place when H_2PO_4^- lose electrons and form HPO_4^{2-} and reduction takes place when H_2PO_4^- gain electrons and form H_3PO_4.

Hence, the two types of reactions always redox reaction are, Single-displacement reaction and Disproportionation reaction.

mina [271]3 years ago
7 0
Single displacement and combustion reactions are ALWAYS redox.
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A wave has a frequency of 3,5MHz and a wavelength of 85,5 m. What is the wave velocity through
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Answer:

velocity = 29925×10⁶ m/s

Explanation:

Given data:

Frequency = 35 MHz

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MHz to Hz

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Formula:

<em>velocity = Wavelength × Frequency</em>

velocity = 855 m × 35×10⁶ Hz

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5 0
3 years ago
Fill in the left side of this equilibrium constant equation for the reaction of benzoic acid (HC_6H_5CO_2) with water.
il63 [147K]

Answer:

[C₆H₅COO⁻][H₃O⁺]/[C₆H₅COOH] = Ka

Explanation:

The reaction of dissociation of the benzoic acid in water is given by the following equation:

C₆H₅-COOH + H₂O  ⇄  C₆H₅-COO⁻  +  H₃O⁺    (1)

The dissociation constant of an acid is the measure of the strength of an acid:

HA ⇄ A⁻ + H⁺        (2)

K_{a} = \frac{[A^{-}][H^{+}]}{[HA]}      (3)

<em>Where the dissociation constant of the acid (Ka) is equal to the ratio of the concentration of the dissociated forms of the acid, [A⁻][H⁺], and the concentration of the acid, [HA].     </em>

So, starting from the equations (2) and (3), the constant equation for the dissociation reaction of benzoic acid in water, of the equation (1), is:

K_{a} = \frac{[C_{6}H_{5}COO^{-}][H_{3}O^{+}]}{[C_{6}H_{5}COOH]}

I hope it helps you!          

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3 years ago
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32 = 0.693 / λ 
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Nt = Nο eΛ(-λt)          (2)

Where Nt is atoms at t time, λ is decay constant and t is the time taken.
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