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mash [69]
3 years ago
15

A hydrogen ion, H+, is the same as a.... PLEASEEE

Chemistry
1 answer:
sdas [7]3 years ago
5 0

It is the same as a proton. That is why, if hydrogen was a molecule not an ion, one electron is needed to 'cancel' out the proton.

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4 years ago
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Please help with chemistry question... It would help me tremendously and if you can, please show work :)?
Alexxandr [17]

Answer:

5.06 atm

Explanation:

Step 1:

Data obtained from the question. This includes:

Mass of S2O = 175g

Volume (V) = 16600 mL

Temperature (T) = 195°C

Pressure (P)

Step 2:

Determination of the number of mole of S2O in 175g of S2O.

Mass of S2O = 175g

Molar Mass of S2O = (32x2) + 16 = 64 + 16 = 80g/mol

Number of mole of S2O =.?

Number of mole = Mass/Molar Mass

Number of mole of S2O = 175/80

Number of mole of S2O = 2.1875 moles

Step 3:

Conversion to appropriate units.

It is essential to always express the various variables in the right units of measurement in order to obtain the desired answer in the right units.

For volume:

1000mL = 1L

Therefore, 16600mL = 16600/1000 = 16.6L

For temperature:

Temperature (Kelvin) = temperature (celsius) + 273

Temperature (celsius) = 195°C

Temperature (Kelvin) = 195°C + 273 = 468K

Step 4:

Determination of the pressure.

The pressure can be obtained by the application of the ideal gas equation. This is illustrated below:

Volume (V) = 16.6L

Temperature (T) = 468K

Number of mole (n) = 2.1875 moles

Gas constant (R) = 0.082atm.L/Kmol

Pressure (P) =

PV = nRT

P x 16.6 = 2.1875 x 0.082 x 468

Divide both side by 16.6

P = (2.1875 x 0.082 x 468) /16.6

P = 5.06 atm

Therefore, the pressure is 5.06 atm

6 0
3 years ago
Which term can be used to describe the process in the reaction below? 2 NaHCO3 (s) → Na2CO3 (s) + H2O (g) + CO2 (g)
Setler79 [48]

Answer:

Decomposition

Explanation:

If we look at the process;

2 NaHCO3 (s) → Na2CO3 (s) + H2O (g) + CO2 (g)

We can see that NaHCO3 was broken down into Na2CO3, H2O and CO2.

The breakdown of one compound to yield other chemical compounds is known as decomposition.

Hence the NaHCO3 was decomposed in the process above.

4 0
3 years ago
A person struggles very hard to lift a large boulder. He puts in so much effort, he starts to sweat, his heart rate increases, a
Tems11 [23]
No, according to physics no work has been done.

Work must have been done by muscular force but in terms of physics no work has been done.

In physics,work is said to be done only if the force applied produced some kind of displacement in the direction of force.

In this example provided, no work has been done since the boulder doesn't get displaced,it continues to remain at its original position.

Hope This Helps You!
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Answer:

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Explanation:

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