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DiKsa [7]
4 years ago
11

Which graph represents an exothermic reaction?

Chemistry
1 answer:
OLga [1]4 years ago
4 0

Answer:

A

Explanation:

got it right on edge2020

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A tank has a volume of 0.1 m3 and is filled with He gas at a pressure of 5 x 106 Pa. A second tank has a volume of 0.15 m' and i
GarryVolchara [31]

Answer:

P=5.6*10^{6} Pa

Explanation:

Consider that, as the system is adiabatic, U_{1}= U_{2} where U1 and U2 are the internal energies before the process and after that respectively.

Consider that: U=H-PV, and that the internal energy of the first state is the sum of the internal energy of each tank.

So, H_{1}-P_{1}V_{1}=H_{2}-P_{2}V_{2}\\H_{1}^{A} -P_{1}^{A}V_{1}^{A}+H_{1}^{B} -P_{1}^{B}V_{1}^{B}=H_{2}-P_{2}V_{2}

Where A y B are the tanks. The enthalpy for an ideal gas is only function of the temperature, as the internal energy is too; so it is possible to assume: H_{1}=H_{2}\\H_{1}^{A}+H_{1}^{B} =H_{2}

So, P_{1}^{A}V_{1}^{A}+P_{1}^{B}V_{1}^{B}=P_{2}V_{2}

Isolating P_{2},

P_{2}=\frac{P_{1}^{A}V_{1}^{A}+P_{1}^{B}V_{1}^{B}}{V_{2}}

V_{2}=V_{1}^{A}+V_{1}^{B}=0.25m^{3}

So,

P_{2}=\frac{5000000*0.1+6000000*0.15}{0.25}=5600000Pa=5.6*10^{6} Pa

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3 years ago
How will the temperature of the water be affected by the dissolving of the lithium oxide?
lesantik [10]

Answer:

i can Help you but iam using my phone so typing is really hectic. reach me via app on +254743503332

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Your answer would be c.
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In a double-replacement reaction, the _____.
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 In a double-replacement reaction, the _____.?


There are many more interesting things to ask about double replacement reactions than are contained in the list given here. But the only correct choice is: 

C.reactants are two ionic compounds

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What is the formula of this<br> inorganic salt hydrate?
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Salt hydrates are an important class of PCMs. An inorganic salt hydrate (hydrated salt or hydrate) is an ionic compound in which the ions attract a number of water molecules, which are then trapped inside the crystal lattice. A hydrated salt has the generic formula MxNy. nH2O.

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