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Aneli [31]
2 years ago
6

2C4H10+ 13O2→ 8CO2+ 10H2O

Chemistry
1 answer:
katen-ka-za [31]2 years ago
8 0

Answer:

Combustion reaction

Explanation:

......

....

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A cyanide solution with avolume of 12.73 mL was treated with 25.00 mL of Ni2+solution (containing
natima [27]

Answer:

The molarity of this solution is 0,09254M

Explanation:

The concentration of the Ni²⁺ solution is:

Ni²⁺ + EDTA⁴⁻ → Ni(EDTA)²⁻

0,03935L × 0,01307M = 5,143x10⁻⁴ moles Ni²⁺ ÷ 0,03010L =<em>0,01709M Ni²⁺</em>

25,00 mL of this solution contain:

0,01709M × 0,02500L = 4,2716x10⁻⁴ moles of Ni²⁺

The moles of Ni²⁺ that are in excess and react with EDTA⁴⁻ are:

0,01015L × 0,01307M = 1,3266x10⁻⁴ moles of Ni²⁺

Thus, moles of Ni²⁺ that react with CN⁻ are:

4,2716x10⁻⁴ - 1,3266x10⁻⁴ = 2,9450x10⁻⁴ moles of Ni²⁺

For the reaction:

4CN⁻ + Ni²⁺ → Ni(CN)₄²⁻

Four moles of CN⁻ react with 1 mole of Ni²⁺:

2,9450x10⁻⁴ moles of Ni²⁺ × \frac{4 mol CN^-}{1 molNi^{2+}} = <em>1,178x10⁻³ moles of CN⁻</em>

As the volume of cyanide solution is 12,73mL. The molarity of this solution is:

<em>1,178x10⁻³ moles of CN⁻ ÷ 0,01273L = </em><em>0,09254M</em>

I hope it helps!

5 0
2 years ago
Please help me I need this
klio [65]
It would be:
1.D
2.A
3.B
4.C

7 0
3 years ago
Ms. Garcia's science students are studying scale models. For her science project, Sarah has decided to make a scale model of the
strojnjashka [21]

Answer:

D. 109 cm

hope this helped :)

8 0
3 years ago
Read 2 more answers
Calculate the pH of a 2.0 M H2SO4 solution.
noname [10]
 <span>H2SO4 gives 2 moles oh H+ per mole of acid 

[H2SO4] = 2M so [H+] = 4M 

pH = -log(4) = -.6 

Therefore, the pH </span><span>of a 2.0 M H2SO4 solution is -0.6
</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
5 0
3 years ago
Read 2 more answers
The formula for calcium oxide is CaO. What are the formulas for magnesium oxide and strontium oxide?
Hunter-Best [27]

Answer:

Formula of magnesium oxide is MgO and formula of strontium oxide is SrO

Explanation:

Ca, Mg and Sr are same group bivalent metals.

Oxygen is a bivalent element

In general, formula of a compound made of a cation M^{x+} and an anion A^{y-} is M_{y}A_{x} for x\neq y

When x = y, formula of the compound becomes MA

As both these metals and oxygen are bivalent therefore formula of magnesium oxide is MgO and formula of strontium oxide is SrO.

8 0
3 years ago
Read 2 more answers
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