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Lunna [17]
2 years ago
5

A steam engine depends on what kind of energy conversation

Chemistry
1 answer:
sdas [7]2 years ago
4 0

Answer:

mechanical energy

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Muscle Activity
sasho [114]
I’m pretty sure it would be B
7 0
3 years ago
Read 2 more answers
The standard free energy change for a reaction in an electrolytic cell is always:_________
sattari [20]

Answer: The standard free energy change for a reaction in an electrolytic cell is always positive.

Explanation:

Electrolytic cells use electric currents to drive a non-spontaneous reaction forward.

Relation of standard free energy change and emf of cell

\Delta G^o=-nFE^0_{cell}

where,

\Delta G^o = standard free energy change

  n= no of electrons gained or lost

F= faraday's constant

E^0_{cell} = standard emf

E^0_{cell}   = standard emf = -ve  , for non spontaneous reaction

Thus  \Delta G^o=(-ve)(-ve)=+ve

Thus standard free energy change for a reaction in an electrolytic cell is always positive.

8 0
3 years ago
What mass of C6H8O7 should be used every 7.0 X 10^2mg NaHCO3
Savatey [412]

Mass C₆H₈O₇ : 0.531484 g

<h3>Further explanation</h3>

Reaction

3NaHCO₃ (aq) + C₆H₈O₇ (aq) → 3 CO₂ (g) + 3 H₂O (l) + Na₃C₆H₅O₇ (aq)

MW NaHCO₃ : 84 g/mol

mass NaHCO₃ : 7.10² mg=0.7 g

mol NaHCO₃ :

\tt mol=\dfrac{0.7}{84}=0.0083

mol C₆H₈O₇ :

\tt \dfrac{1}{3}\times 0.0083=0.00277

MW C₆H₈O₇ : 192 g/mol

mass C₆H₈O₇ :

\tt mass=0.00277\times 192=0.53184

4 0
3 years ago
A sample of a compound contains 3.21 g of sulfur and 11.4 g of fluorine. Which of the following represents the empirical formula
Sergeeva-Olga [200]

Answer:

The empirical formula is SF6 (option E)

Explanation:

Step 1: Data given

Mass of sulfur = 3.21 grams

Mass of fluorine = 11.4 grams

Molar mass sulfur = 32.065 g/mol

Molar mass fluorine = 19.00 g/mol

Step 2: Calculate moles

Moles = mass /molar mass

Moles sulfur = 3.21 grams / 32.065 g/mol

Moles sulfur = 0.100 moles

Moles fluorine = 11.4 grams / 19.00 g/mol

Moles fluorine = 0.600 moles

Step 3: Calculate mol ratio

We divide by the smallest amount of moles

S: 0.100 / 0.100 = 1

F : 0.600 / 0.100 = 6

The empirical formula is SF6 (option E)

7 0
3 years ago
How much heat is given off when 869 g iron bar cools from 94 degrees celsius to 5
melomori [17]

Answer:

Heat given off was -34.34kJ

Explanation:

Mass of iron bar = 869g

Initial temperature (T1) = 94°C

Final temperature (T2) = 5°C

Specific heat capacity of iron (c) = 0.444J/g°C

Heat energy (Q) = Mc∇T

Q = heat energy

c = specific heat capacity

∇T = change in temperature

M = mass of the substance

Q = mc∇T

∇T = T2 - T1

Q = Mc(T2 -T1)

Q = 869 * 0.444 * (5 - 94)

Q = 385.836 * -89

Q = -34339.404J

Q = -34.34kJ

The heat given of was -34.34kJ

4 0
3 years ago
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