What is y <-x+2 on a graph???

Find the missing side lengths. Answers are in simplest radical form with the denominator rationalized

Roman55 [17]

Answer:

Option B.

Step-by-step explanation:

The given triangle is a right angle triangle.

In a right angle triangle,

$\tan \theta=\dfrac{Perpendicular}{Base}$

In the given triangle,

$\tan (45^{\circ})=\dfrac{v}{7}$

$1=\dfrac{v}{7}$

$7=v$

Using Pythagoras theorem, we get

$hypotenuse^2=Perpendicular^2+Base^2$

$u^2=v^2+7^2$

$u^2=7^2+7^2$

$u^2=2(7^2)$

Taking square root on both sides, we get

$u=\sqrt{2(7^2)}$

$u=7\sqrt{2}$

Therefore, the correct option is B.

6 0

3 years ago

A circle is centered at (2, -5) and has radius 3. Write its equation in standard form. A) (x + 2)2 + (y - 5)2 = 3 B) (x - 2)2 +

ki77a [65]

D.
$(x - h)^{2} + {(y - k)}^{2} = r^{2}$
Where (h, k) is the center of the circle and the radius is squared.

4 0

4 years ago

Read 2 more answers

Plis i need help whit this questionss

zmey [24]

Question 1: x+2 = 8 doesn't belong in the given equations.

Question 2: The possible values for y are 0,1 and 2

Step-by-step explanation:

Question: Which one doesn't belong?

We will solve each equation one by one to get which equation doesn't belong with others

So,

$x+4 = -2\\x+4-4 = -2-4\\x = -6$

$x+5 = -1\\x+5-5 = -1-5\\x = -6$

$x+2 = 8\\x+2-2 = 8-2\\x = 6$

$3-x=9\\3-x-3 = 9-3\\-x = 6\\x = -6$

Hence,

x+2 = 8 doesn't belong in the given equations.

Question 2:

Given equation is:

$x+y = 5$

It is given that the values of x will be greater than 2 and less than 6 so values of x can be 3,4 and 5

So,

$3+y = 5\\y = 5-3\\y = 2\\\\4+y = 5\\y = 5-4\\y = 1\\\\5+y = 5\\y = 5-5\\y = 0$

Hence,

The possible values for y are 0,1 and 2

So,

x+2 = 8 doesn't belong in the given equations.

The possible values for y are 0,1 and 2

Keywords: Linear equation, variables

Learn more about linear equations at:

#LearnwithBrainly

8 0

3 years ago

Answer both questions and get 20 points and brainliest

WINSTONCH [101]

Answer:

item 30.

d. 1 ½ as we can see the difference between the each x value is 2 and y value is more of 1 and 2.

items 31.

a. ⅖ as similar to upper question the difference between each x value is 2 and y value is 5 so ⅖

8 0

3 years ago

Simplify:9-1÷2÷27^2÷3

sammy [17]

First let's calculate the exponents.

$27^2 : 729 = 9-1\div \:2\div \:729\div \:3$

Now we should multiply and divide.

$1\div2\div729\div3:\frac{1}{4374} = 9-\frac{1}{4374}$

Now we should add and subtract.

$9-\frac{1}{4374} :\frac{39365}{4374} = \frac{39365}{4374}$

Convert the improper fractions into mixed numbers.

$8\frac{4373}{4374}$

Answer :

$8\frac{4373}{4374}$

5 0

3 years ago