Answer:
<em>13.1</em>
Step-by-step explanation:
A = bh
~~~~~~~
= 16 , 
= 9
A = 16 × 9 = 144
From another side area of parallelogram with hight "h" base "b"
11h = 144
<em>h</em> = 144 ÷ 11 ≈ <em>13.1</em>
Answer:
the answer may be this: 8 √3
I think its this <span> 14 - 3*57 = 14 - 171 = -157 </span>
That I can not understand it looks weird.
Answer:
sin(A-B) = 24/25
Step-by-step explanation:
The trig identity for the differnce of angles tells you ...
sin(A -B) = sin(A)cos(B) -sin(B)cos(A)
We are given that sin(A) = 4/5 in quadrant II, so cos(A) = -√(1-(4/5)^2) = -3/5.
And we are given that cos(B) = 3/5 in quadrant I, so sin(B) = 4/5.
Then ...
sin(A-B) = (4/5)(3/5) -(4/5)(-3/5) = 12/25 + 12/25 = 24/25
The desired sine is 24/25.
