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3 years ago

Name 2 things that travel well through metal?

Chemistry

1 answer:

MArishka [77]3 years ago

5 0

Answer:

Heat, electricity x

Explanation:

Hope this helps! :) x

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Help please 20points

lions [1.4K]

Answer:

Explanation:

D is the answer because this is the only one having to do with genetics. Fox's genetics changed because it's environment changed.

6 0

3 years ago

Read 2 more answers

Consider the following reaction at 298 K:

faltersainse [42]

Answer :

$\Delta S_{sys}$ = -1622.8 J/K

$\Delta S_{surr}$ = -94.6 J/K

$\Delta S_{univ}$ = 0 J/K

Explanation : Given,

$\Delta H$ = -483.6 kJ

The given chemical reaction is:

$2H_2(g)+O_2(g)\rightarrow 2H_2O(g)$

First we have to calculate the value of $\Delta S_{sys}$ .

$\Delta S_{sys}=\frac{\Delta H}{T}$

$\Delta S_{sys}=\frac{-483.6kJ}{298K}$

$\Delta S_{sys}=-1.6228kJ/K=-1622.8J/K$

Entropy of system = -1622.8 J/K

As we know that:

Entropy of system = -Entropy of surrounding = 1622.8 J/K

and,

Entropy of universe = Entropy of system + Entropy of surrounding

Entropy of universe = -1622.8 J/K + (1622.8 J/K)

Entropy of universe = 0

8 0

3 years ago

Calculate the volume in Liters of 15 moles of Neon gas (at STP)

Archy [21]

Step by step solution:

Its given;
Moles of neon at STP is 15 mol
We are required to calculate the volume;
According to molar gas volume, 1 mole of a gas occupies a volume of 22.4 liters at STP.
That is, 1 mole of a gas = 2.4 L
Therefore;
1 mole of Neon gas = 22.4 L

Volume = Moles of the gas × molar gas volume
= 15 mol × 22.4 L/mol
= 336 L

5 0

3 years ago

What concentration of OH is required to created a pOH of 1.3.

Crank

Answer:

0.0501

Explanation:

OH=10^-poH

OH=10^-1.3

=0.0501

6 0

3 years ago

Which of the following aqueous solutions will have the lowest freezing point? a. 0.75 m (NH4)3PO4 b. 1.0 m CaSO4 c. 1.0 m LiCl d

Nataly [62]

Answer: a. 0.75m (NH4)3PO4 will have the lowest freezing point .

Explanation: Freezing point decreases as the concentration of the solute substance increases. Assuming the same solvent for all of them, for instance water.

∆T= i.Kf.b

∆T= freezing point depression

i= vant Hoff factor

Kf= molality

Assuming water to be the solvent for all Kf=1.86°C/M

VANT HOFF FACTORS :

For (NH4)3PO4

This has 3 ionic bonding and 1 covalent bonding making it 4 bond

Therefore i=4

For CaSO4

This has 1 metallic bond and 1 covalent bond making it 2 bond.

Therefore i=2

For LiCl

This has 1 metallic bond and 1 non metallic bond making it 2 bond.

Therefore i=2

For CH3OH

This has only 1 covalent bond.

Therefore i=1

MOLALITY:

(NH4)3PO4 = 0.75M

CaSO4= 1.0M

LiCl= 1.0M

CH3OH= 1.5M

FREEZING POINT DEPRESSION:

For (NH4)3PO4

∆T= 4×0.75×1.86=5.58°C

For CaSO4

∆T= 2×1.0×1.86=3.72°C

For LiCl

∆T = 2×1.0×1.86= 3.72°C

For CH3OH

∆T= 1×1.5×1.86=2.79°C

REMEMBER THE HIGHER THE FREEZING POINT DEPRESSION THE LOWER THE FREEZING POINT.

FREEZING POINT DEPRESSION IS THE CHANGE IN THE FREEZING POINT PROPORTIONAL TO THE AMOUNT OF SOLUTE ADDED THE THE SOLUTION.

THEREFORE THE ONE WITH THE LOWEST FREEZING POINT IS (NH4)3PO4

4 0

4 years ago