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Alenkasestr [34]
2 years ago
15

Why would sand and water be an example of a heterogeneous mixture? Select all that apply. Chemical bonds are formed between the

sand and water. *The mixture does not have a uniform appearance. *The mixture does not maintain a uniform composition. The sand stays suspended in the water.
Chemistry
2 answers:
drek231 [11]2 years ago
7 0

The mixture does not maintain uniform composition and sand stays suspended in water. And no, there no chemical bond between sand and water.

Sliva [168]2 years ago
6 0
<span>The mixture does not have a uniform appearance. </span><span>
The sand stays suspended in the water. (The sand sinks actually but I think by saying suspended, they mean it does not dissolve in water)</span>
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Which of these is an acid A(Vinegar
ololo11 [35]
Vinegar is the only thing listed
8 0
3 years ago
A certain water tower hold 4.6×10^5 gallons of water. find the volume of that water in liters.​
Readme [11.4K]

Answer: 1741289L

Explanation:

1 gallon = 3.78541 L

4.6×10^5 gallons = 4.6×10^5 x 3.78541 = 1741289L

6 0
2 years ago
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g A solution contains 100mM NaCl, 20mM CaCl2, and 20mM urea. We would say this solution is __________ compared to a 300 mOsM sol
ICE Princess25 [194]

Answer:

A solution contains 100mM NaCl, 20mM CaCl2, and 20mM urea. We would say this solution is hypotonic compared to a 300 mOsM solution and hypotonic compared to a cell with 300 mOsM (non-penetrating solutes) interior.

Explanation:

The osmolarity is calculated from the molar concentration of the active particles in the solution. We have a solution that is composed of NaCl, CaCl₂ and urea.

When they are dissolved in water, they dissociate into particles as follows:

NaCl → Na⁺ + Cl⁻  (2 particles per compound)

CaCl₂ → Ca²⁺ + 2 Cl⁻ (3 particles per compound)

urea: not dissociation (1 particle per compound)

Then, we have to calculate the osmolarity of the solution. We multiply the molarity of each compound by the number of particles produced by the compound in water:

Osm = (100 mM NaCl x 2) + (20 mM CaCl₂ x 3) + (20 mM urea x 1) = 280 mOsm

Compared with 300 mOsm, 280 mOsm has a lower osmolarity, so it is a hypotonic solution.

To compare with a cell's osmolarity, we have to consider only the non-penetrating solutes. Urea is considered a penetrating solute for mammalian cells. So, the osmolarity of non-penetrating solutes (NaCl  and CaCl₂) is calculated as:

Osm (non-penetrating solutes) = (100 mM NaCl x 2) + (20 mM CaCl₂ x 3) = 260 mOsm

Therefore, we have:

Compared to 300 mOsm solution ⇒ 280 mOsm solution is a hypotonic solution

Compared to a cell with 300 mOsm ⇒ 260 mOsm solution is hypotonic

4 0
2 years ago
How many hydrogen atoms are in 5.20 mol of ammonium sulfide?
Fofino [41]
1) Molecular formula of ammonium sulfide

(NH4)2 S

2) That means that there are 2*4 = 8 atoms of hydrogen in each molecule of ammoium sulfide, so in 5.20 mol of molecules will be 8 * 5.20 mol = 41.6 moles of atoms of hydrogen

3) To pass to number of atoms multiply by Avogadro's number: 6.022 * 10^23

41.6 moles * 6.022 * 10^23 atoms / mol = 250.5 * 10^23 = 2.50 * 10^25 atoms

Answer: 2.50 * 10^25
8 0
3 years ago
2 H2 + 2 NO → N2 + 2 H2O the observed rate expression, under some conditions, is: rate = k[NO]2 Which of the following mechanism
guapka [62]

Explanation:

Rate law is defined as the rate of a reaction is directly proportional to the concentration of reactants at constant temperature.

               Rate \propto [\text{concentration of reactant}]^{n}

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where,     k = rate constant

                n = order of reaction

For the given reaction, 2H_{2} + 2NO \rightarrow N_{2} + 2H_{2}O

Hence, its rate will be as follows.

                   Rate = k[H_{2}][NO]

Also, it is known that slowest step in a chemical reaction is the rate determining step.

Hence, for the given rate law correct reaction is as follows.

Step 1 : H_{2} + NO \rightarrow N + H_{2}O (slow)

Balancing this equation it becomes H_{2} + 2NO \rightarrow N_{2}O + H_{2}O (slow)

Step 2: N_{2}O + H_{2} \rightarrow N_{2} + H_{2}O (fast)

4 0
3 years ago
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