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3 years ago

C +02 → CO2 What type of chemical reaction is taking place in this

Chemistry

1 answer:

pshichka [43]3 years ago

7 0

Answer:

Synthesis

Explanation:

Decomposition is where one compound splits into two or more

Single replacement is when an element switches with another element in a compound

Combustion is when something combines with oxygen to produce water and carbon dioxide

Double replacement is like single but two compounds switch their elements

You might be interested in

How many grams of sodium phosphate are formed by the reaction of 10 g of sodium with phosphoric acid?

Norma-Jean [14]

Answer:

23.8g of sodium phosphate are formed

Explanation:

Based on the reaction of sodium, Na, with phosphoric acid, H₃PO₄:

3Na + H₃PO₄ → Na₃PO₄ + 3/2 H₂

<em>3 moles of sodium produce 1 mole of sodium phosphate</em>

<em />

To solve this question we must find the moles of sodium in 10g. Using the chemical reaction we can find the moles -And the mass- of sodium phosphate produced, as follows:

<em>Moles Na -Molar mass: 22.99g/mol-</em>

10g * (1mol / 22.99g) = 0.435 moles Na

<em>Moles Na₃PO₄:</em>

0.435 moles Na * (1mol Na₃PO₄ / 3mol Na) = 0.145 moles Na₃PO₄

<em>Mass Na₃PO₄ -Molar mass: 163.94g/mol-</em>

0.145 moles Na₃PO₄ * (163.94g/mol) =

<h3>23.8g of sodium phosphate are formed</h3>

8 0

2 years ago

11.0 L of hydrogen and 5.52 L of oxygen are exploded together in a reaction tube. What volume of water vapor was formed, at STP?

Marysya12 [62]

Answer:

11.0 L

Explanation:

The equation for this reaction is given as;

2H2 + O2 --> 2H2O

2 mol of H2 reacts with 1 mol of O2 to form 2 mol of H2O

At STP;

1 mol = 22.4 L

This means;

44.8 L of H2 reacts with 22.4 L of O2 to form 44.8 L of H2O

In this reaction, the limiting reactant is H2 as O2 is in excess.

The relationship between H2 and H2O;

44.8 L = 44.8 L

11.0 L would produce x

Solving for x;

x = 11 * 44.8 / 44.8

x = 11.0 L

4 0

3 years ago

What does the prefix trans-indicate?

fredd [130]

Answer:

B. The carbons on either side of the double bond are Pointed in opposite directions

7 0

3 years ago

Write the products of these double-replacement reaction. Then balance each equation. a) NaOH(aq) + Fe(NO3)3 (aq)---> Iron (II

pashok25 [27]

Answer:

3NaOH (aq) + Fe(NO₃)₃ (aq) → Fe(OH)₃ (s) + 3NaNO₃ (aq)

Explanation:

Step 1: RxN

NaOH (aq) + Fe(NO₃)₃ (aq) → Fe(OH)₃ (s) + NaNO₃ (aq)

Step 2: Balance RxN

We need 3 OH's on both sides.

We also need 3 NO₃'s on both side.

This will make it so we also need 3 Na's on both side

3NaOH (aq) + Fe(NO₃)₃ (aq) → Fe(OH)₃ (s) + 3NaNO₃ (aq)

6 0

3 years ago

You start out with 800 moles of a radioactive substance. After 24 hours, 100 moles remain. What is the half-life of the substanc

Nookie1986 [14]

The half life of the substance is 8 hours , Option D is the correct answer.

What is Half Life ?

Half-life is the time required by an unstable element to reduce to half of its initial value.

The term is commonly used in nuclear physics.

The formula is

$\rm N(t) = \; N_{0} \;(\dfrac{1}{2} )^{\frac{t}{t_{1/2} } }$

N(t) = quantity of the substance remaining

N ₀ = initial quantity of the substance

t = time elapsed

$\rm t_{1/2}$ = half life of the substance

The data given in the question is N ₀ = 800 moles , N(t)= 100 , t= 24 hours

$\rm t_{1/2} =\; ?$

Substituting values in the equation

$\rm 100 = \; 800 \;(\dfrac{1}{2} )^{\frac{24}{t_{1/2} } }$

$\rm \dfrac{100}{800} = \;(\dfrac{1}{2} )^{\frac{24}{t_{1/2} } }\\\\\rm \dfrac{1}{8} = \;(\dfrac{1}{2} )^{\frac{24}{t_{1/2} } }\\\\\rm (\dfrac{1}{2})^{3} = \;(\dfrac{1}{2} )^{\frac{24}{t_{1/2} } }\\\\\rm 3=\dfrac{24}{t_{1/2} }\\\\t_{1/2}= \dfrac{24}{3}\\\\t_{1/2} = 8 hours$

Therefore half life of the substance is 8 hours , Option D is the correct answer.

To know more about Half Life

brainly.com/question/24710827

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3 0

2 years ago