I hope this helps you out. It is very tedious
If 4y-2=26 then 4y=26+2
4y=28 divide both side by 4
y=28/4=7 opt A
For any point to be in the first quadrant, it must have a positive "x" value and "y" value.
If x = 1 then y = 2, a point with both x and y positive values which would be in the First Quadrant.
Answer:
y = 6
Step-by-step explanation:
-4 + 3y = 14
+4 +4
3y = 18
---- ----
3 3
y = 6
