Explanation:
It is known that the change in Gibb's free energy varies with temperature as follows.
= ![\Delta H(T_{f}) - \Delta C_{p,m} (T - T_{f}) - T[\Delta S(T_{f}) - \Delta C_{p,m} ln (\frac{T}{T_{f}})]](https://tex.z-dn.net/?f=%5CDelta%20H%28T_%7Bf%7D%29%20-%20%5CDelta%20C_%7Bp%2Cm%7D%20%28T%20-%20T_%7Bf%7D%29%20-%20T%5B%5CDelta%20S%28T_%7Bf%7D%29%20-%20%5CDelta%20C_%7Bp%2Cm%7D%20ln%20%28%5Cfrac%7BT%7D%7BT_%7Bf%7D%7D%29%5D)
(assumption)
= 
= 
As, T = 
= (-3 + 273) = 270 K, 
.
Therefore, calculate the change in Gibb's free energy as follows.
= 
= -65.93 J/mol K + 0.62 J/mol K
= -65.31 J/mol K
Thus, we can conclude that Gibbs energy of freezing for the given reaction is -65.31 J/mol K.
Answer:
B
P
K
Explanation:
K: 203pm
B: 84pm
P: 107pm
There isn't an E on the Periodic Table?!
If<span> the </span>circuit<span> is </span>broken<span> at any point there won't be any current that </span>will<span> flow. ... </span>circuit<span>. In this case, </span>if<span> one of the </span>bulbs<span> blew out, the </span>other bulb<span> would not be able to ... string of </span>light bulbs<span>, and one burned out, the remaining </span>bulbs<span> would also turn off</span>
Answer:
b. H3O c. H2SO4 d. HNO3
Explanation:
The hydrogen bonds can be form with molecules that have free electron pairs and hydrogen atoms. In the case of NH4 molecule, the "free" electron pair in the nitrogen is not free because there is an hydrogen occuping them, and, in fact, this molecule has a positive charge. The other acids have free electron pairs in the oxigen, nitrogen or sulfur.
