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nikdorinn [45]
2 years ago
8

What is one way to speed up a chemical reaction without otherwise affecting the reaction? A. add a catalyst B. decrease surface

area C. change the products D. change the reactants
Chemistry
2 answers:
alexandr402 [8]2 years ago
8 0
A. add a catalyst <span>is the correct answer.</span>
frutty [35]2 years ago
7 0
A. add a catalyst is the correct answer.

A catalyst never takes part in the reaction, so it does not affect the reaction.

Hope this helps~
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A doctor's Order is 0.125 g of ampicillin. The liquid suspension on hand contains 250 mg/s. How many milliliters (mL) of the sus
Molodets [167]

Answer:

c) 2.5 mL

Explanation:

Solution

Doctors order = 0.125g

and

The liquid suspension concentration = 250 mg/5ml

= 0.250g/5ml

Or 0.05g/ml

Amount of ml of suspension required = 0.125g/(0.05g/ml) = 2.5ml

7 0
3 years ago
What is the mole ratio needed to determine the mass of phosphorus trifluoride produced from the reaction of 120 g of phosphorus
Vitek1552 [10]

Answer:

\frac{4molPF_3}{1molP_4}

Explanation:

Hello

In this case, given the reaction:

P_4(s)+6F_2(g)\rightarrow 4PF_3(g)

It means that since the coefficients preceding phosphorous and phosphorous trifluoride are 1 and 4, the correct mole ratio should be:

\frac{4molPF_3}{1molP_4}

Because given the mass of phosphorous it is convenient to convert it to moles and then cancel it out with the moles on bottom of the mole ratio.

Bes regards!

8 0
2 years ago
CaCo3+2HCL Cacl2+h2o+co2
Rasek [7]

Answer:

Here

Explanation:

This is an acid-base reaction (neutralization): CaCO3 is a base, HCl is an acid.

6 0
2 years ago
Which word would not make this statement true?
statuscvo [17]
The first step in the two-step process of making a solution is the breakdown of the solute source into Atomic particles
for a solution to break the solute must be dissociated and break into the atomic particles
so correct option is D
hope it helps
6 0
2 years ago
What assumptions do we make in order to use the Henderson-Hasselbalch equation? a. Both the weak acid and its conjugate base are
zepelin [54]

Answer:

The final and initial concentration of the acid and it's conjugate base are approximately equal, that is we use the weak acid approximation.

Explanation:

The Henderson-Hasselbalch is used to calculate the pH of a buffer solution. It depends on the weak acid approximation.

Since the weak acid ionizes only to a small extent, then we can say that [HA] ≈ [HA]i

Where [HA] = final concentration of the acid and [HA]i = initial concentration of the acid.

It also follows that [A^-] ≈ [A^-]i where [A^-] and[A^-]i refer to final and initial concentrations of the conjugate base hence the answer above.

7 0
3 years ago
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