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2 years ago

I need a testable question that I can research and write an essay on. Please help

Physics

1 answer:

pishuonlain [190]2 years ago

4 0

Explanation:

how does pollution affect global warming?

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PLEASE HELP FAST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Leno4ka [110]

The flashlight's beam will all be refracted towards a central axis. But, this is still dependent on the type of lens that is used for the said activity. The speed of light will vary depending whether the lens is a concave or a convex lens. The exit point of the light will always head towards the central axis.

4 0

3 years ago

Read 2 more answers

You’re driving your car towards an intersection. A Porsche is stopped at the red light. You’re traveling at 36 km/h (10 m/s). As

34kurt

Your position at time $t$ , relative to the stop line:

$x_1=-15\,\mathrm m+\left(10\dfrac{\rm m}{\rm s}\right)t$

The Porsche's position:

$x_2=\dfrac12\left(3\dfrac{\rm m}{\mathrm s^2}\right)t^2$

a. You pass the Porsche immediately after the time it takes for $x_1=x_2$ :

$-15\,\mathrm m+\left(10\dfrac{\rm m}{\rm s}\right)t=\dfrac12\left(3\dfrac{\rm m}{\mathrm s^2}\right)t^2\implies t=2.3\,\rm s$

at which point you both will have traveled 7.8 m from the stop line.

b. The equation in part (a) has two solutions. The Porsche passes you at the second solution of about $t=4.4\,\rm s$ , at which point you both will have traveled 29 m.

c. At time $t$ , the Porsche is moving at velocity

$v=\left(3\dfrac{\rm m}{\mathrm s^2}\right)t$

so that at the moment it passes you, its speed is 13 m/s, which is about 46.8 km/h and below the speed limit, so neither of you will be pulled over.

6 0

3 years ago

The average radial velocity of galaxies in the Hercules cluster is 10,800 km/s. (a) using H0 = 73 km/s/Mpc, find the distance to

ArbitrLikvidat [17]

Answer:

a) 147.95 Mpc

Explanation:

Using Hubble's formula

$v = H_od$

where;

v = radical velocity

$H_o$ = Hubble's constant

d = distance

Given that:

The average radial velocity of galaxies in the Hercules cluster v = 10,800 km/s

Also using $H_o$ = 73 km/s/ Mpc ; we make distance d the subject of the formula:

Then distance d can be written as:

$d = \frac{v}{H_o}$

$d = \frac{10,800 \ km/s}{73 \ km/s/Mpc}$

d = 147.95 Mpc

Now, if the Hubble constant had a smaller value, then for a given velocity the distance to the galaxy will increase because distance d is inversely proportional to $H_o$

i.e

d ∝ $\frac{1}{H_0}$