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wolverine [178]
3 years ago
12

WILL GIVE BRAINLIEST

Physics
2 answers:
kaheart [24]3 years ago
8 0
Mass of girl =55kg
acceleration due to gravity =9.8m/s^2

So, the force she is applying on the floor must equal
55× 9.8 N
(Because force =mass ×acceleration)
=539N

Now, according to newton's third law the floor must be applying the same force on the body in the opposite direction.
So the force applied here by the floor is 539N upward.


Option "C" is the correct one.
Rudik [331]3 years ago
7 0
The answer is at least 539 N up
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What is your mass in kilograms if you weigh 120 pounds
schepotkina [342]

It depends where you are.

-- If you weigh 120 pounds on the Moon,
then your mass is  329.1 kilograms.

-- If you weigh 120 pounds on Mars,
 then your mass is  143.8 kilograms.

-- If you weigh 120  pounds on the Earth,
then your mass is  54.4 kilograms.

6 0
3 years ago
 How many centimeters are there in meter? b. 10 c. d 1000 e. 10000 100 2. A centimeter is equal to 1 inch b.½inch C 1/2.54 inch
astra-53 [7]

Answer:

a) There are 100 centimeters in 1 meter.

b) \texttt{A cm is equal to }\frac{1}{2.54}\texttt{ inch}

Explanation:

a) We have the conversion

         1 m = 100 cm

   So there are 100 centimeters in 1 meter.

b) 1 inch = 2.54 cm

    1cm=\frac{1}{2.54}inch

   \texttt{A cm is equal to }\frac{1}{2.54}\texttt{ inch}

8 0
3 years ago
Why is it important to understand the concept of density ?
N76 [4]
Density applies to many if not all aspects of life.  With density you can explain why ice floats.   You can explain why oxygen is on the earth, and not floating around in space( or being replaced by another gas).  You can also explain why heat rises while cold air sinks.
8 0
3 years ago
Place the left charge at the 2 cm position and the right one at the 4 cm position. Vary the left and right charge to the values
Vlad1618 [11]

Answer:

Explanation:

Force between two charges can be expressed as follows

F = k q₁ q₂ / d²

q₁ and q₂ are two charges , d is distance between them , k is a constant whose value is 9 x 10⁹

distance between charges is fixed which is 4 -2 = 2 cm = 2 x 10⁻² m

force between 1μC and  4μC

= 9 x 10⁹ x 1 x 4 x 10⁻¹² / ( 2 x 10⁻² )²

= 9 x 10 = 90 N

force between 4μC and  1μC

= 9 x 10⁹ x 4 x 1 x 10⁻¹² / ( 2 x 10⁻² )²

= 9 x 10 = 90 N

force between 2μC and  2μC

= 9 x 10⁹ x 2 x 2 x 10⁻¹² / ( 2 x 10⁻² )²

= 9 x 10 = 90 N

force between 1μC and  2μC

= 9 x 10⁹ x 1 x 2 x 10⁻¹² / ( 2 x 10⁻² )²

= 4.5 x 10 = 45 N

force between 1μC and  8μC

= 9 x 10⁹ x 1 x 8 x 10⁻¹² / ( 2 x 10⁻² )²

= 18 x 10 = 180 N

force between 2μC and  8μC

= 9 x 10⁹ x 1 x 8 x 10⁻¹² / ( 2 x 10⁻² )²

= 36 x 10 = 360 N

Left Charge   Right Charge Resulting force(N)

1μC                     4μC                  90 N

4μC                   1μC                    90 N

2μC                  2μC                    90 N

1μC                    2μC                   45 N

1μC                  8μC                    180 N

2μC                  8μC                  360 N

5 0
3 years ago
A sample of carbon dioxide (C°p,m = 37.11 J K−1 mol−1) of mass 2.80 g at 27°C is allowed to expand reversibly and adiabatically
My name is Ann [436]

Answer:

182 to 3 s.f

Explanation:

Workdone for an adiabatic process is given as

W = K(V₂¹⁻ʸ - V₁¹⁻ʸ)/(1 - γ)

where γ = ratio of specific heats. For carbon dioxide, γ = 1.28

For an adiabatic process

P₁V₁ʸ = P₂V₂ʸ = K

K = P₁V₁ʸ

We need to calculate the P₁ using ideal gas equation

P₁V₁ = mRT₁

P₁ = (mRT₁/V₁)

m = 2.80 g = 0.0028 kg

R = 188.92 J/kg.K

T₁ = 27°C = 300 K

V₁ = 500 cm³ = 0.0005 m³

P₁ = (0.0028)(188.92)(300)/0.0005

P₁ = 317385.6 Pa

K = P₁V₁¹•²⁸ = (317385.6)(0.0005¹•²⁸) = 18.89

W = K(V₂¹⁻ʸ - V₁¹⁻ʸ)/(1 - γ)

V₁ = 0.0005 m³

V₂ = 2.10 dm³ = 0.002 m³

1 - γ = 1 - 1.28 = - 0.28

W =

18.89 [(0.002)⁻⁰•²⁸ - (0.0005)⁻⁰•²⁸]/(-0.28)

W = -67.47 (5.698 - 8.4)

W = 182.3 = 182 to 3 s.f

7 0
3 years ago
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