The problem ask to calculate the initial speed of the sled that was shove up a frictionless 28 degree incline and reaches a maximum vertical height of 1.35 m than it started and the initial speed of the sled is 5.14 m/s. I hope you are satisified with my answer
Answer:
4ft
Step-by-step explanation:
500=pir^2h
r^2=500/(10*pi)
r=3.989ft
(2y² + 7y + 11) - (8y² - 5y + 7) you can distribute the negative sign to the second expression and then combine the like terms
new expression: (2y² + 7y + 11) (-8y² + 5y - 7)
2y² and -8y² equals -6y²
7y and 5y equals 12y
11 and -7 equals 4
The answer is -6y² + 12y + 4
<span>To evaluate the given expression, we need the values of each variable and substitute these values to the expression. Then, go on with the operations involved.
</span>4x - y - 2z
4(-2) - (3) - 2(-2)
-8 - 3 + 4
-7
You would use 539 and square it on you cal. just once. Then once you do that the answer is not going to be a whole number it is going to have a decimal, so the answer would be 23.22.
