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Serhud [2]
3 years ago
7

What is the equation for the acid ionization constant of HClO2?

Mathematics
1 answer:
jarptica [38.1K]3 years ago
6 0
<span>[H+] x [(CIO2)-]/[HCIO2]</span>
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Please Help 6-10 or just one of them
Free_Kalibri [48]

Answer:

6) 20

7) I think is 2.5 (im not sure)

8) 7

Step-by-step explanation:

6) (5x+9)+(3x+11)=180

    8x+20=180

         -20   -20

          8x=160

Divide 8 on each side

            x=20

7) (17x+1)=(20x-14)

   17x+15 =20x

   +17         +17

     15 = 37x

divide 15 on each side

X=2.5

8) (3x+3)+(10-4)=90

    (3x)+(10x-1)

      13x-`1=90

            +1   +1

         13x=91

Divide 13 on each side

x=7

5 0
2 years ago
Evaluate the surface integral. s x ds, s is the triangular region with vertices (1, 0, 0), (0, −2, 0), and (0, 0, 12).
aniked [119]
Parameterize the surface by

\mathbf r(s,t)=(1-s)(0,0,12)+s\bigg((1-t)(1,0,0)+t(0,-2,0)\bigg)
\implies\mathbf r(s,t)=(x(s,t),y(s,t),z(s,t))=(s-st,-2st,12-12s)

where (s,t)\in(0,1)\times(0,1). We have

\|\mathbf r_s\times\mathbf r_t\|=\|(1-t,-2t,-12)\times(-s,-2s,0)\|=2\sqrt{181}s

The surface integral is then

\displaystyle\iint_Sx\,\mathrm dS=2\sqrt{181}\int_{s=0}^{s=1}\int_{t=0}^{t=1}s(s-st)\,\mathrm dt\,\mathrm ds
=\displaystyle2\sqrt{181}\left(\int_{s=0}^{s=1}s^2\,\mathrm ds\right)\left(\int_{t=0}^{t=1}(1-t)\,\mathrm dt\right)
=\dfrac{\sqrt{181}}3
7 0
3 years ago
Can someone please help me?
makkiz [27]
Second one...................
7 0
3 years ago
What is the surface area of a rectangular prism that has i height of 2 length of 5 and width of 13​
BaLLatris [955]

Answer:

A=202

Step-by-step explanation:

A=2(wl+hl+hw)

2·(13·5+2·5+2·13)=202

7 0
3 years ago
Make y the subject to the following questions
skelet666 [1.2K]
In this question it basically wants you to leave Y alone in a side of the equation.

In this case,
For 3y=c

y=\frac{c}{3}

For Ay=w

y=\frac{w}{A}

For Y/c=w
Y=cw

For y/a=2c
y=2ac

For a=y+p
y=a-p

For C=y-k
y=C+k

5 0
3 years ago
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