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Inessa05 [86]
3 years ago
5

if air has dry bulb temperature of 2 and the wet bulb temperature of -2 . what is the relative humidity

Physics
1 answer:
Nezavi [6.7K]3 years ago
3 0
100% I think that is the answer.
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The landing of a spacecraft is cushioned with the help of airbags. During its landing on Mars, the velocity of downward fall is
statuscvo [17]
You can use the impulse momentum theorem and just subtract the two momenta.
P1 - P2 = (16-1.2)(11.5e4)=1702000Ns
If you first worked out the force and integrated it over time the result is the same
5 0
4 years ago
Read 2 more answers
6. A car moving in a straight line at constant speed:
ddd [48]

Answer:

D. has no overall force acting on it.

Explanation:

Why?

Because in a straight line at the constant speed means the car moving in the same velocity, which is not acceleration neither deceleration, and it cannot be on a downhill slope. So the correct answer is

<h3>→ D. has no overall force acting on it.</h3>
8 0
3 years ago
PLEASE HELP AND HURRY
andreyandreev [35.5K]
C
I took the tests earlier hope this helps
7 0
4 years ago
How heavy is an object that displaces 400N of water in a pool?
julia-pushkina [17]
All we can say is that the object's volume is about 41 liters. That's the same as the volume of water displaced.

We can't say anything about the object's weight. There is no direct connection between the weight of the object and the weight of the water it displaces.
7 0
3 years ago
A thin flake of mica (n=1.58) is used to cover one slit of a double-slit interference arrangement. The central point on the wiew
Llana [10]

To develop this problem it is necessary to apply the optical concepts related to the phase difference between two or more materials.

By definition we know that the phase between two light waves that are traveling on different materials (in this case also two) is given by the equation

\Phi = 2\pi(\frac{L}{\lambda}(n_1-n_2))

Where

L = Thickness

n = Index of refraction of each material

\lambda = Wavelength

Our values are given as

\Phi = 7(2\pi)

L=t

n_1 = 1.58

n_2 = 1

\lambda = 550nm

Replacing our values at the previous equation we have

\Phi = 2\pi(\frac{L}{\lambda}(n_1-n_2))

7(2\pi) = 2\pi(\frac{t}{\lambda}(1.58-1))

t = \frac{7*550}{1.58-1}

t = 6637.931nm \approx 6.64\mu m

Therefore the thickness of the mica is 6.64μm

3 0
3 years ago
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