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padilas [110]
3 years ago
7

Two blocks of aluminum (specific heat c=0.22 cal/g Celsius) with masses of 1000 g and 100 g are at a temperature of 70 c. Which

block has more thermal (internal) energy? Explain why?
Physics
1 answer:
Liula [17]3 years ago
3 0

Internal thermal energy is given as

Q = mCT

so it will depend on the product of mass, specific heat capacity and temperature.

so here we know that both blocks are identical with same initial temperature

So the block with larger mass must have more internal energy

So here the correct answer would be the block with mass 1000g

block with mass 1000 g must have more internal energy

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You flip a coin straight up if the coin reaches a high point of 0.25 m above where you released it what was the initial speed?
Julli [10]

Answer: 2.21 m/s

Explanation:

Given

Coin reaches a height of  0.25 m above the launch point

Suppose u is the initial speed of the coin

Using the equation of motion

\Rightarrow v^2-u^2=2as\\

Putting values

\Rightarrow 0^2-u^2=2\times g\times s=2\times (-9.8)\times 0.25\\\Rightarrow u^2=4.9\\\Rightarrow u=2.21\ m/s

Thus, the initial velocity is 2.21 m/s

6 0
3 years ago
Plasmodium belong to which kingdom​
musickatia [10]

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plasmodium belongs to kingdom protista

4 0
3 years ago
Light of wavelength 550 nm comes into a thin slit and produces a diffraction pattern on a board 8.0 m away. The first minimum da
FrozenT [24]

Answer:

Width of the slit will be equal to 1.47 mm

Explanation:

We have given wavelength of the light \lambda =550nm=550\times 10^{-9}m

Distance D = 8 m

Distance between first minimum dark fringe and the central maximum is 2 mm

So x=3\times 10^{-3}m

We have to find the width of the slit

For the first order wavelength is equal to \lambda =\frac{x}{D}\times a, here a width of slit

So a=\frac{\lambda D}{x}=\frac{550\times 10^{-9}\times 8}{3\times 10^{-3}}=1466.666\times 10^{-6}=1.47mm

So width of the slit will be equal to 1.47 mm

5 0
3 years ago
Phase, color, and ductility are all examples of what type of property?
Mama L [17]
Physical properties.
7 0
3 years ago
A 2.3 kg block of copper is heated at atmospheric pressure such that its temperature increases from 6 oC to 90 oC. How much heat
Shtirlitz [24]

Answer:

the  heat absorbed by the block of copper is 74368.476J

Explanation:

Hello!

To solve this problem use the first law of thermodynamics that states that the heat applied to a system is the difference between the initial and final energy considering that the mass and the specific heat do not change so we can infer the following equation

Q=mCp(T2-T1)

Where

Q=heat

m=mass=2.3kg

Cp=0.092 kcal/(kg C)=384.93J/kgK

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T1= initial temperature=6 C

solving

Q=(2.3kg)(384.93\frac{J}{kgC} )(90C-6C)=74368.476J

the  heat absorbed by the block of copper is 74368.476J

7 0
3 years ago
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