The energy required to raise the temperature of the air in a room by 5.0°C is 336 kJ
U = 
m ΔT
U = Energy
= Specific heat
m = Mass
ΔT = Change in temperature
ρ = Density
V = Volume
ρ = 1000 g / m³ (Dry air )
= 1 J / g K
ΔT = 5 °C
V = 4 * 4 * 3
V = 48 m³
m = ρ V
m = 1000 * 48
m = 48000 g
U = 1 * 48000 * 7
U = 336000 J
U = 336 kJ
Therefore, the energy required to raise the temperature of the air in a room by 5.0°C is 336 kJ
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(.140*25)+(75*0)= 3.5
3.5 = (.140 + 75)v
(3.5)/(.140 + 75) = v = .04657
which rounds up to .05 m/s
Hope this helps!!!!!!!!!!!!!
In a transformer, energy is carried from the primary coil to the secondary coil by magnetic field in the iron core.
To find the answer, we have to know more about the transformer.
<h3>
How transformer works?</h3>
- An item utilized in the transfer of electric energy is a transformer.
- AC current is used for transmission.
- It is frequently used to modify the supply voltage between circuits without altering the AC frequency.
- The fundamentals of mutual and electromagnetic induction govern how the transformer operates.
- Magnetic field through the primary coil changes when primary coil current varies. the iron core of the secondary coil likewise has a magnetic field.
- EMF is therefore generated in the secondary coil.
Thus, we can conclude that, in a transformer, energy is carried from the primary coil to the secondary coil by magnetic field in the iron core.
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